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sveticcg [70]
3 years ago
9

Describe how the metal probably increases the reaction rate, identify whether this an example of homogeneous or heterogeneous ca

talysts, and explain how you know.
Chemistry
1 answer:
Ulleksa [173]3 years ago
4 0

Explanation:

The metal probably helps to speed up the reaction rate a/c to collision theory, reactant molecules must collide with a reasonable direction by either weakening bonds in reactant molecules to make them extra reactive or by attaching reactant molecules in the exact direction to react.

This is known as an example of heterogeneous catalysis because the catalyst is solid and the reactants are liquid or gases mixture. In this catalysis, the catalyst is present in a different phase compare to the reactants.

You might be interested in
A chemist determines by measurements that 0.0550 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of
shtirl [24]

The mass of nitrogen gas that participated in the chemical reaction is 1.54g

HOW TO CALCULATE MASS OF AN ELEMENT:

  • Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;

  • mass (M) = molar mass (MM) × number of moles (n)

According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.

  • The molecular mass of nitrogen gas (N2) = 14.01(2)

= 28.02g/mol

Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:

  • Mass (g) = 0.0550 mol × 28.02 g/mol

  • Mass = 1.5411

Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g

Learn more: brainly.com/question/18269198

6 0
3 years ago
Use the reaction and bond information to answer the question. H2 CO2 → CH2O2 Reactant bond energies: H–H is 432 kJ/mol, C=O is 7
Anna11 [10]

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.

The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.

<h3>Computation for the energy absorbed</h3><h3 />

The given reaction has been:

\rm H_2\;+\;CO_2\;\rightarrow\;CH_2O_2

The bond energy of the reactant has been:

H-H bond energy = 432 kJ/mol

2 C=O bond energy= 799 kJ/mol

The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol

The total energy of the reactant has been 1231 kJ/mol

The bond energy of the product has been:

C-O bonds = 358 kJ/mol

C=O bonds = 745 kJ/mol

1 C-H bond = 413 kJ/mol

1 O-H bond = 467 kJ/mol

The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol

The total energy of the product has been 1,983 kJ/mol

According to the law of conservation of energy:

\text{Product energy=Reactant energy + energy absorbed}

Substituting the values for energy absorbed:

\text{1,983 kJ/mol=1231\;kJ/mol+ energy absorbed}\\\rm Energy\;absorbed=1983-1231\;kJ/mol\\Energy\;absorbed=752\;kJ/mol

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

Learn more about bond energy, here:

brainly.com/question/866298

7 0
2 years ago
There are 12 liters of nitrogen gas in a sample. How many moles of N2 in this sample?
Firlakuza [10]

Answer:

0.54 moles of N2

Explanation:

First remember to find the volume in moles, 1 mole equals 22.4 liters.

So now use the dimensional analysis to show your work.

12 liters of N2 *  1 mol /22.4 liters of N2

Now calculate this. 12 * 1/22.4 or 12/ 22.4

12/22.4 = 0.535714286.

12 has two significant digits.

With that, The answer rounds to 0.54.

So that the final answer is 0.54 moles.

Hope it helped!

6 0
3 years ago
What is the half-life of a first-order reaction if it takes 4.4 x 102 seconds for the concentration to decrease from 0.50 M to 0
elena55 [62]

Answer: The half-life of a first-order reaction is, 3.3\times 10^2s

Explanation:

All the radioactive reactions follows first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = ?

t = time taken = 440 s

[A_o] = initial amount of the reactant = 0.50 M

[A] = left amount =  0.20 M

Putting values in above equation, we get:

k=\frac{2.303}{440s}\log\frac{0.50}{0.20}

k=2.083\times 10^{-3}s^{-1}

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

Putting values in this equation, we get:

t_{1/2}=\frac{0.693}{2.083\times 10^{-3}s^{-1}}=332.69s=3.3\times 10^2s

Therefore, the half-life of a first-order reaction is, 3.3\times 10^2s

4 0
3 years ago
What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?
Kay [80]

Answer:

29.232 l

Explanation:

6.023x10^23 mole of nitrogen =22.4 l

7.83×10^23 mole of nitrogen =

22.4/(6.023×10^23)×7.83×10^23

=29.232 l

4 0
3 years ago
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