If the heat necessary to warm 565.0 g of water from a temperature of T1 = 22.0 °C to T2 = 80.0 °C were somehow converted to tran
1 answer:
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Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that initially the grass hopper is at rest at the ground position
Now the acceleration is given as
distance of the legs that it stretched is given as
so we have
Part b)
time taken to reach this speed is given as
Part c)
as the grass hopper reach the maximum height its final speed would be zero
so we will have
Answer:
X = 50 g
Explanation:
Please see attached photo for explanation.
From the attached photo,
Anticlock–wise moment = X × 20
Clockwise moment = 100 × 10
Anticlock–wise moment = clockwise moment
X × 20 = 100 × 10
X × 20 = 1000
Divide both side by 20
X = 1000 / 20
X = 50 g
Therefore, the value of X is 50 g
Answer:
The speed of the ball B is 6.4 m/s. The direction is 50 degrees counterclockwise.
Explanation:
Assuming the collision is elastic, use the conservation of momentum to solve this problem. The conservation law implies that:
(the total momentum of the two balls is the same before (index 0) and after (index 1) the collision). Since B is stationary and A and B have the same mass, this simplifies to:
and allows us to determine the velocity of ball B after the collision:
The above involves vectors. Your problem suggests to use the component method, which I am assuming means solving the above equation separately along the x and y axes. Define x to align with the original line of motion of the ball A before the collision, and y to be perpendicular to x, pointing up:
We just need to compute the x- and y-components of the known velocity of the ball A. Drs. Sine and Cosine come to help here.
so
The speed of the ball B is . The direction (angle from horizontal) is
, i.e., 50 degrees counterclockwise.