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andrew11 [14]
3 years ago
8

Where do most stars fall on the Hertzsprung-Russell diagram?

Physics
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

Most of the stars occupy the region in the diagram along the line called the main sequence. During the stage of their lives in which stars are found on the main sequence line, they are fusing hydrogen in their cores.

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When making a budget, you should prioritize ___________ before "__________." A. Needs/wants B. Wants/needs C. Electricity/Water
cestrela7 [59]

Answer:

Needs, Wants

Explanation:

Needs are necessary, wants are not

7 0
4 years ago
What is the acceleration of a car that goes from 0 MS to 60 MS and six seconds
Len [333]
A = Δv/Δt
a = v2-v1/t2-t1
a = 60MS - 0MS / 6 seconds
a = 60 MS/ 6 seconds
a = 10 m/s^2
8 0
3 years ago
Two spherical conductors are separated by a distance much larger than either of their radii. Sphere A has a radius of 11.5 cm an
bonufazy [111]

Explanation:

As the given spheres are connected by a thin wire so, the potential on the spheres are the same.

          \frac{q_{1}}{r_{1}} = \frac{q_{2}}{r_{2}} ......... (1)

Hence, total charge will be as follows.

              q_{1} + q_{2} = Q = -95.5 nC .......... (2)

Using the above two equations, the final equation will be as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

and,    q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}

Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

                     = \frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}

                     = 82.714 nC

Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.

                       

5 0
3 years ago
Which particle of the atom has a positive charge? A. proton B. electron C. nucleus D. neutron
mafiozo [28]
Two of these choices are correct. The nucleus of the atom has a positive charge, because of the positively charged protons in there.
3 0
3 years ago
6. What is the wavelength of a wave that is traveling at 30 m/s and has a frequency of 3.2 Hz?
lidiya [134]

Answer:

6. 9.4 m

7. 1050 m/s.

Explanation:

6. Determination of the wavelength

Velocity (v) = 30 m/s

Frequency (f) = 3.2 Hz

Wavelength (λ) =?

v = λf

30 = λ × 3.2

Divide both side by 3.2

λ = 30 / 3.2

λ = 9.4 m

Thus, the wavelength of the wave is 9.4 m.

7. Determination of the speed of the wave.

Wavelength (λ) = 350 m

Frequency (f) = 3 Hz

Velocity (v) =.?

v = λf

v = 350 × 3

v = 1050 m/s

Thus, the speed of the wave is 1050 m/s

6 0
3 years ago
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