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Ksivusya [100]
3 years ago
5

According to Newton’s law of universal gravitation, which statement is true?

Physics
1 answer:
Rufina [12.5K]3 years ago
7 0

According to Newton's 2nd Law of Motion, if a constant force acts on an object, the object will accelerate.

According to Newton’s law of universal gravitation, the gravitational attraction between the Earth and an object causes a constant force to act on the object.

So, because of that force, Falling objects accelerate as they approach the ground.  <em> (B)</em>

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German physicist Werner Heisenberg related the uncertainty of an object's position (Δx) to the uncertainty in its velocity (Δv)Δ
laiz [17]

Answer:

5.79*10⁻⁹ m is the uncertainty in the position.

Explanation:

Heisenberg's uncertainty principle assumes that it is not possible to know exactly all the data regarding the behavior of particles. In other words, at the subatomic level, it is impossible to know at the same moment where a particle is, how it moves and what its speed is.

So, Heisenberg's Uncertainty Principle gives a relationship between the standard deviation of an object's position and its momentum.

Δp*Δx= h/(4π)

where

  • Δp the standard deviation of the object's momentum,
  • Δx the standard deviation of the object's position,
  • h=6.63*10⁻³⁴ J.s is the Planck's constant.

By definition, the momentum of the electron equals the product of its mass and velocity. So, being the mass constant, you can said:

Δp= m*Δv

Replacing in the expresion of the Heisenberg's Uncertainty Principle:

m*Δv*Δx= h/(4π)

Then you know:

  • m=9.11*10⁻³¹ kg
  • Δv=0.01*10⁶ m/s
  • h=6.63*10⁻³⁴ J.s= 6.63*10⁻³⁴ (N*m)*s=6.63*10⁻³⁴ [(kg*m*s⁻²)*m]*s= 6.63*10⁻³⁴ kg*m²*s⁻¹

Replacing:

*Δx=6.63*10⁻³⁴ kg*m²*s⁻¹/(4π)

Taking π=3.14 and solving:

Δx=\frac{6.63*10^{-34}  kg*m^{2} *s^{-1} }{4*3.14*9.11*10^{-31}  kg*0.01*10^{6}  m/s}

Δx=5.79*10⁻⁹ m

<u><em>5.79*10⁻⁹ m is the uncertainty in the position.</em></u>

3 0
3 years ago
A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
masha68 [24]

Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

  • original frequency of the source, f=1200\ Hz
  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

3 0
3 years ago
True or False: Objects fall at a constant speed.
Maksim231197 [3]

Answer:

Explanation:

true

8 0
3 years ago
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a runner makes one lap around a 200m track in 25s, what is the runners (a) average speed and (b) average velocity
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5 0
3 years ago
a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e
natima [27]

Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

5 0
3 years ago
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