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Sav [38]
3 years ago
8

4. A coconut falls from a tree and lands on the ground 2 s later. What

Physics
2 answers:
Ulleksa [173]3 years ago
6 0

Answer:

vf=19.6

h=19.6

FROM FIRST EQUATION that is vf=vi+gt

then vf = 0+9.8*2=19.6m/s

FROM SECOND EQUATION that is H=vi*t+1/2gt²

then H=0*2+1/2*9.8*2²=19.6

Nady [450]3 years ago
5 0

Answer:

W

g

​

=mgs .......(1)

Change in velocity of coconut is,

E=

2

1

​

m(u−v)

2

=−

2

1

​

m(v)

2

........(2)

Now, total work done on coconut is equal to change in kinetic energy hence,

W

a

​

+W

g

​

=

2

1

​

mv

2

where, W

a

​

is  work done by air resistance.

Using (1) and (2), we get

W

a

​

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B is the right one

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How does reducing the mass of a moving object by half (1/2) change its kinetic energy?​
allochka39001 [22]
Kinetic energy = 1/2 m v²
If we reduce the mass by half > m/2
Kinetic energy = 1/2 m/2 v²
We should know that 1/2 × 1/2 = 1/4
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7 0
3 years ago
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 11 m from the takeoff point. part a if the
Svetllana [295]
We have that the maximum rank of the kangaroo is given by:
 R = v0 ^ 2 sin (2θ) / g
 where,
 v0 = initial velocity
 θ = angle of the velocity vector formed from the horizontal
 g = gravity
 Clearing the speed we have:
 v0 ^ 2 = (R * g) / (sin (2θ))
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 answer
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6 0
3 years ago
Read 2 more answers
Imagine a system where a block rests on an inclined plane. The block is then given an initial push so that it starts sliding dow
katen-ka-za [31]

Answer:

the correct affirmation is the 3

Explanation:

Let's analyze the problem with Newton's second law before looking at the claims.

X axis parallel to the plane, positive down

      F -fr + Wₓ = ma

Y Axis perpendicular to the plane

      N -Wy = 0

With trigonometry

     Wₓ = W sin θ

     Wy = w cos θ

Let's multiply by the displacement along the plane, to relate to the work, which has as expression W = F d

     F d -fr d + Wx d = ma d

Push                  W₁ = Fd

frictional force  W₂ = -fr d

gravity               W₃ = Wx d

    W₁ + W₃ -W₂ = m a d

Analysis affirmations:

R1) false. The work of gravity is the subtraction    

R2) false. Each force contributes according to its magnitude

R3) true. In the equation we see that, if the acceleration is zero, W2 = W1 + W3

R4) False. It equals the difference

the correct affirmation is the 3

6 0
3 years ago
At one moment during a walk around the block, there are four forces exerted upon Fido - a 10.0 kg dog. The forces are:
Ann [662]

Explanation:

Given that,

Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)

Fnorm = 64.5 N, up

Ffrict = 27.6 N, left

Fgrav = 98 N, down

(a) Resolution of the applied force:

Horizontal component,

F_x=F\cos\theta\\\\=67\times \cos(30)\\\\=58.02\ N

Vertical component,

F_y=F\sin\theta\\\\=67\times \sin(30)\\\\=33.5\ N

(b) Net horizontal force :

F_x=58.02+(-27.6),\ \text{frictional force act in opposite direction of motion}\\\\F_x=30.42\ N

It is positive, it will act in right side

Net vertical force :

F_y=33.5+64.5+(-98),\ \text{gravitational force acts in downward direction}\\\\F_y=0

Hence, it is clear that the net force is in horizontal direction i.e. 30.42 N due right side.

7 0
3 years ago
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