Hi there!
To find the final velocity of an object dropped from rest, we can used the simplified equation:
vf = √2gh
Plug in the given values: (g = 9.8 m/s²)
vf = √2(9.8)(100) ≈ 44.272 m/s
We are given with a force in the middle of a rope measuring 10 m and an angle of sagging of 10 degrees from the horizontal. The tension of the rope is equal to the hypotenuse of the right triangle.
sin 10 = 50 kg * 9.8 m/s2 / T
Tension = 2821. 80 N
Answer:
The answer for this question is 146 neutrons
The initial compression of the spring is determined as 0.54 m.
<h3>What is the compression of the spring?</h3>
The compression of the spring is determined by applying the principle of conservation of linear momentum as follows;
E = U
mgh = ¹/₂kx²
2mgh = kx²
x² = 2mgh/k
x = √(2mgh/k)
where;
- m is the mass of the projetcile
- h is the height
- k is the spring constant = 0.07 N/cm = 7 N/m
- x is the compression of the spring
x = √(2 x 0.021 x 9.8 x 5)/7)
x = 0.54 m
Learn more about compression of spring here: brainly.com/question/2114706
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