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Norma-Jean [14]
3 years ago
13

When using the right-hand rule to determine the direction of the magnetic force on a charge, which part of the hand points in th

e direction that the charge is moving?
Physics
2 answers:
aliina [53]3 years ago
8 0

Answer:

The correct answer is the thumb of the right hand.

Explanation:

The Force will follow Lorentz's law, a vectorial product: F= q*v x B, where:

q is the charge of the particle.

v is its velocity.

x indicates the vector product.

B is the magnetic field.

Being a vector product F the plane formed by v and B will be perpendicular. To determine the sense we will apply the variant of the rule of the right hand. The fingers of the right hand without the thumb run from vector v to vector B, so in this case, the force will have a sense upwards. It must be said that the rule always indicates the direction of the positive charge if the charge is negative the direction of F is inverse (downwards).

Have a nice day!

Y_Kistochka [10]3 years ago
6 0
Your thumb points in the direction of the charge.

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Newton’s Second Law of motion defines force in terms of mass and acceleration, F= ma. Which of the following is false? The term
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Answer:

The forces creating the net force must lie in the same direction.

Explanation:

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5 0
3 years ago
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

8 0
3 years ago
A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s
Leokris [45]

Answer:

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Explanation:

The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:

T=m\frac{v^2}{r}

where

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m is the mass of the rock

v is the speed

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At the beginning,

T = 50.4 N

v = 21.1 m/s

r = 2.51 m

So we can use the equation to find the mass of the rock:

m=\frac{Tr}{v^2}=\frac{(50.4)(2.51)}{21.1^2}=0.284 kg

Later, the radius of the string is decreased to

r' = 1.22 m

While the speed is increased to

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Substituting these new data into the equation, we find the tension at which the string breaks:

T'=m\frac{v'^2}{r'}=(0.284)\frac{(51.6)^2}{1.22}=619.8 N

5 0
3 years ago
How far will a man travel in 15 min driving his car down the highway at an average speed of 24 m/?s
emmasim [6.3K]

Answer:

21.6 km

Explanation:

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\frac{21600}{1000}= 21.6 km

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