To solve this problem it is necessary to use the concepts given through the ideal gas equation.
For this it is defined that
Where,
P = Pressure
V = Volume
R = Gas ideal constant
T = Temperature
n = number of moles.
In this problem we have two states in which the previous equation can be applied, so
From the first state we can calculate the Volume
Replacing
From the state two we can calculate now the number of the moles, considering that there is a change of 0.8 from Volume 1, then
Therefore there are 3.3moles of air left in the tire.
Answer:
A) Its density will decrease
Explanation:
When an object is heated, its volume increases. This is due to the fact that the particles in the medium vibrate more (if it is a solid) or they move more (if it is a liquid or a gas), therefore they tend to occupy a larger space.
At the same time, the mass of the object does not change, because the mass just represents the amount of matter contained in the object, so it does not increase/decrease at different temperatures.
The density of an object is defined as the ratio between the mass (m) and the volume (V):
We said that the mass remains unchanged while the volume increases: since the density is inversely proportional to the volume, this means that the density decreases.
Answer:
If one of the parents is white and the other is brown, their offspring will be either white or brown with equal probabilities. Rabbits in this population mate randomly; thus, the probability of mating two white rabbits is the same as the probability of mating between two brown rabbits.
Explanation:
This type of circuit is a closed series circuit
The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 
.
First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.
In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.
The electric field E created by the point charge q at any point P, located at a distance r, is defined as:
where K is the constant of Coulomb's law.
In this case, you know:
- K= 9×10⁹
- q= 20 uC=20×10⁻⁶ C
- r= 1 m
Replacing in the definition of electric field:
Solving:
<u><em>E=180000 </em></u><u><em /></u>
Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 .
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