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uranmaximum [27]
3 years ago
9

A step-down transformer providing electricity for a residential neighbor-hood has exactly 2680 turns in its primary. when the po

tential differenceacross the primary is 5850 v, the potential difference at the secondary is120 v. how many turns are in the secondary?
Physics
1 answer:
Fynjy0 [20]3 years ago
6 0
The turns ratio is equal to the voltage ratio. Let n1 and n2 be the primary and secondary turns. Then
5850V/120V=n1/n2
48.75=2680/n2
n2=2680/48.75
n2=55
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Setler79 [48]

Answer:

Position A/Position E

K = E, U = 0

Position B/Position D

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Position C

K = 0, U = E

Explanation:

Let suppose that ball-Earth system represents a conservative system. By Principle of Energy Conservation, total energy (E) is the sum of gravitational potential energy (U) and translational kinetic energy (K), all measured in joules. In addition, gravitational potential energy is directly proportional to height (h) and translational kinetic energy is directly proportional to the square of velocity.

Besides, gravitational potential energy is increased at the expense of translational kinetric energy. Then, relative amounts at each position are described below:

Position A/Position E

K = E, U = 0

Position B/Position D

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3 0
2 years ago
Which circuit has the larger equivalent resistance: a circuit with two 10 ohm resistors connected in parallel or a circuit with
Ganezh [65]

Answer:

A circuit with two 10 ohm resistors connected in series.

Explanation:

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\frac{1}{Rt} = \frac{1}{R1} + \frac{1}{R2}   So if R1=R2= 10  \frac{1}{Rt} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10}   Rt =\frac{10}{2} =5 ohm

The formula for the equivalent resistance for resistors in series is

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What will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors?
dsp73

Hello!

Recall for resistors in parallel:
\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}

We can begin by calculating the total resistance:
\frac{1}{R_t} = \frac{1}{10} +  \frac{1}{10} + \frac{1}{10}}\\\\\frac{1}{R_t} = \frac{3}{10}\\\\R_t = \frac{10}{3} = \boxed{3.333 \Omega}

Now, we can calculate the current using Ohm's Law:
V = iR\\\\i = \frac{V}{R}

V = Voltage of battery (V)
i = Current (A)

R = Resistance (Ω)

Plug in the given voltage and the total resistance we solved for.

i = \frac{15}{3.33} = \boxed{4.5 A}

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