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2 years ago

Which term refers to the rate of change of motion?

Physics

1 answer:

borishaifa [10]2 years ago

4 0

Answer:

The term that refers the rate change of motion is acceleration.

Explanation:

The rate at which the motion changes is called as the acceleration. It is a vector quantity with the SI unit meters. There is device to measure the acceleration called as accelerometer. The acceleration is also affected by the increase and the decrease of the force and mass. It is directly proportional to it. The acceleration increases with force, but found to be decreasing with mass. It can be calculated by taking the product of displacement by time.

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A 2 kg toy car moves at a speed of 5 m/s.<br> What is the kinetic energy of the car?

ANTONII [103]

Answer:

<h2>The answer is 25 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

$KE = \frac{1}{2} m {v}^{2} \\$

m is the mass

v is the velocity

From the question we have

$KE = \frac{1}{2} \times 2 \times {5}^{2} \\ = 1 \times {5}^{2}$

We have the final answer as

Hope this helps you

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1 year ago

A car slows down from 80 km/h to 60 km/h in 2 seconds.

Andreyy89

Answer:

please mark brainlist

Explanation:

Initial speed u=80 km/h=80×185=22.22 m/s

Final speed v=60 km/h=60×185=16.67 m/s

Using v=u+at

Or 16.67=22.22+α×5

⟹ a=−1.1 m/s2

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2 years ago

Large power plants in the United States currently use what generators.

Natalija [7]

<span>Many power plants in the United States use fossil fuels like natural gas and coal to generate energy, while others use nuclear power. </span>

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2 years ago

A 392 N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 24

alex41 [277]

Answer:

h=12.41m

Explanation:

N=392

r=0.6m

w=24 rad/s

$I=0.8*m*r^{2}$

So the weight of the wheel is the force N divide on the gravity and also can find momentum of inertia to determine the kinetic energy at motion

$N=m*g\\m=\frac{N}{g}\\m=\frac{392N}{9.8\frac{m}{s^{2}}}$

$m=40kg$

moment of inertia

$M_{I}=0.8*40.0kg*(0.6m} )^{2}\\M_{I}=11.5 kg*m^{2}$

Kinetic energy of the rotation motion

$K_{r}=\frac{1}{2}*I*W^{2}\\K_{r}=\frac{1}{2}*11.52kg*m^{2}*(24\frac{rad}{s})^{2}\\K_{r}=3317.76J$

Kinetic energy translational

$K_{t}=\frac{1}{2}*m*v^{2}\\v=w*r\\v=24rad/s*0.6m=14.4 \frac{m}{s}\\K_{t}=\frac{1}{2}*40kg*(14.4\frac{m}{s})^{2}\\K_{t}=4147.2J$

Total kinetic energy

$K=3317.79J+4147.2J\\K=7464.99J$

Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height

$K-W=E_{p}\\7464.99-2600J=m*g*h\\4864.99J=m*g*h\\h=\frac{4864.99J}{m*g}\\h=\frac{4864.99J}{392N}\\h=12.41m$

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2 years ago

If a canadian plane is traveling at 500 miles/hr, how fast is this in m/s?

patriot [66]

223.52 meters per second

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2 years ago