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Solnce55 [7]
3 years ago
7

Which term refers to the rate of change of motion?

Physics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

The term that refers the rate change of motion is acceleration.

Explanation:

The rate at which the motion changes is called as the acceleration. It is a vector quantity with the SI unit meters. There is device to measure the acceleration called as accelerometer. The acceleration is also affected by the increase and the decrease of the force and mass. It is directly proportional to it. The acceleration increases with force, but found to be decreasing with mass. It can be calculated by taking the product of displacement by time.

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Describe how the boiling point of water on top of a mountain would be different from its boiling point at sea level.
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Answer:

At elevated altitudes, any cooking that involves boiling or steaming generally requires compensation for lower temperatures because the boiling point of water is lower at higher altitudes due to the decreased atmospheric pressure.

Explanation:

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3. A cat walks 0.220km North, then 0. 120 km South in a time of 400 seconds. whats the displacement and average velocity?
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Answer:

The rate at which velocity changes with respect to a change in time is called. acceleration.

Explanation:

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You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,
lbvjy [14]

Answer:

The value is T_c  =  12 .1 ^oC

Explanation:

From the question we are told that

The mass of the ice cube is m_i  =  7.50 *10^{-3} \  kg

The temperature of the ice cube is T_i = 0^o C

The mass of the copper cube is m_c  =  0.540 \  kg

The final temperature of both substance is T_f  =  0^oC

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

Q =  m_c  *  c_c *  [T_c  -  T_f ]

The specific heat of copper is c_c  = 385J/kg \cdot  ^oC

Generally the heat gained by the ice cube is mathematically represented as

Q_1 =  m_i * L

Here L is the latent heat of fusion of the ice with value L  =  3.34 * 10^{5} J/kg

So

Q_1 =  7.50 *10^{-3} * 3.34 * 10^{5}

=> Q_1 =  2505 \ J

So

2505  =  0.540  *  385 *  [T_c  - 0 ]

=>    T_c  =  12 .1 ^oC

4 0
2 years ago
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