The change in the standard Gibbs free energy (ΔGº) for the dissociation of nitrous acid (HNO2) at 298 K is 19.09 kJ. If the pH of the solution after equilibrium is reached is 1.30 and the NO2 – concentration at equilibrium is 0.00060 M. What is the equilibrium concentration of HNO2? Hint: Use pH to determine the equilibrium concentration of H+ .
HNO2(aq) H + (aq) + NO2 – (aq)
Answer:
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Answer:
B) 17.98 %
Explanation:
3 Li =21 P = 31 4O 64 == 116
21/116=18.1%
Closest 17.98
Answer:
2.78x10⁻³ m
Explanation:
Nitrogen diffusion in the steel can be expressed using the following equation:
<u>Where:</u>
J: is the diffusion flux = 1.0x10⁻⁷ kgm⁻²s⁻¹
D: is the diffusion coefficient = 1.85x10⁻¹⁰ m²/s
C₁: is the concentration of nitrogen in the steel at the surface = 2 kg/m³
C₂: is the concentration of nitrogen at the distance x₂ = 0.5 kg/m³
x₁: is the distance at the surface = 0
x₂: is the distance to find
Hence, we have:
(1)
Solving equation (1) for x₂:
Therefore, the nitrogen will enter 2.78x10⁻³ m into the sheet.
I hope it helps you!
The balanced equation for the reaction is as follows;
Zn + 2HCl --> ZnCl₂ + H₂
stoichiometry of Zn to HCl is 1:2
limiting reagent is the reactant that is fully consumed in the reaction.
the amount of product formed depends on amount of limiting reactant present.
The excess reactant is when it has been provided in excess and only a fraction of the provided amount is used up in the reaction.
Amount of Zn moles - 0.5 mol
Amount of HCl moles - 0.6 mol
If Zn is provided, number of HCl moles reacted - 0.5 x 2 = 1.0 mol of HCl is required, but only 0.6 mol of HCl is provided.
HCl is therefore the limiting reactant,
Number of Zn moles required - 0.6 mol /2 = 0.3 mol
But 0.5 mol are given, therefore 0.2 mol of Zn is in excess
