Answer : The concentration of NaOH is, 0.336 M
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus, the concentration of NaOH is, 0.336 M
Data Given:
Time = t = 30.6 s
Current = I = 10 A
Faradays Constant = F = 96500
Chemical equivalent = e = 63.54/2 = 31.77 g
Amount Deposited = W = ?
Solution:
According to Faraday's Law,
W = I t e / F
Putting Values,
W = (10 A × 30.6 s × 31.77 g) ÷ 96500
W = 0.100 g
Result:
0.100 g of Cu²⁺ is deposited.
Answer : The value of work done by an ideal gas is, 37.9 J
Explanation :
Formula used :
Expansion work = External pressure of gas × Volume of gas
Expansion work = 1.50 atm × 0.25 L
Expansion work = 0.375 L.atm
Conversion used : (1 L.atm = 101.3 J)
Expansion work = 0.375 × 101.3 = 37.9 J
Therefore, the value of work done by an ideal gas is, 37.9 J
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