Answer:
Option B.
C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O
Explanation:
To know which option is correct, we shall write the balanced equation for the combustion of cellulose. This is illustrated below:
C₆H₁₀O₅ + O₂ —> CO₂ + H₂O
There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 6 before CO₂ as shown below:
C₆H₁₀O₅ + O₂ —> 6CO₂ + H₂O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₆H₁₀O₅ + O₂ —> 6CO₂ + 5H₂O
There are a total of 7 atoms of O on the left side and a total of 17 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:
C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O
Now, the equation is balanced.
Thus, option B gives the correct answer to the question.
I think answer youre looking for is 2Na+O->Na2O . But sadly it is wrong since we dont use atomic oxygen in reactions. It should be rather
4Na+O2 => 2Na2O but it doesnt correspond to ratios given.
We want to take inventory of the right and left side
Right: S=1 O = 2 Li = 2 Se= 1
Left: S= 1 Se=2 Li= 2 O=1
Lets balance out each side because we see we are off by 1 oxygen on the left
Add a coefficient of 2 on the Li2O
Add a coefficient of 2 on the right Li2Se
Now we have So2+ 2Li2Se ---> SSe2+ 2Li2O
or
The equation is already balanced, assuming that there is supposed to be a yields symbol between 2Li2Se and SSe2.
To find out whether or not this equation is balanced, make a little T-chart with the left side of the equation on one side and the left on the other. Next to each element, write down the amount they start off with and make changes as you add coefficients.
Hope this helps!
Your on your own that looks like rocket science