Answer:
The amplitude of the absorbed mass can be found
for ka:
now
![w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg](https://tex.z-dn.net/?f=w%5E2%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bm_%7Ba%7D%20%7D%20%5C%5Cm_%7Ba%7D%20%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bw%5E2%7D%20%3D%5Cfrac%7B125000%7D%7B%5B6000%2A2%5Cpi%20%2F60%5D%5E2%7D%20%3D0.317kg)
Answer:
(a) The Final Temperature is 315.25 K.
(b) The amount of mass that has entered 0.5742 Kg.
(c) The work done is 56.52 kJ.
(d) The entrophy generation is 0.0398 kJ/kgK.
Explanation:
Explanation is in the following attachments.
Answer:
B because as a textile engineer, your job is to help design and create fabric, including the equipment and materials needed for fabrication.
Answer:
Wright Company
Bank Reconciliation
May 31, 2013
Credit side Debit side
Bank statement $26200 | Book balance $27900
<em>Add; </em>
Deposit on May 31 $6400
Bank error $420
Sub-total=$33020
Deductions; | Deduct
ions
Outstanding checks $5800 | Bank service charge $120
Adjusted bank balance $27220 | NSF check $560
Total deduction $680
Adjusted book balance $27220
