Answer:
the correct distance is 202 ft
Explanation:
The computation of the correct distance is shown below:
But before that correction to be applied should be determined
= (101 ft - 100 ft) ÷ (100 ft) × 200 ft
= 2 ft
Now the correct distance is
= 200 ft + 2 ft
= 202 ft
Hence, the correct distance is 202 ft
The same would be relevant and considered too
❎❎❎❎❎❎❎ sorry but that didn't help me that much
Answer:
Explanation:
We define as,
c.V Piston
The energy equation for the piston is
Remember that
So,
Answer:
see explaination
Explanation:
Module VBModule
Function KineticEnergy(ByVal mass As Decimal, ByVal velocity As Decimal) As Decimal
Dim result As Decimal
result = 0.5*mass*velocity*velocity
KineticEnergy = result
End Function
Sub Main()
Dim mass = Console.ReadLine()
Dim velocity = Console.ReadLine()
Console.WriteLine(FormatNumber(CDbl(KineticEnergy(mass,velocity)), 3))
End Sub
End Module