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faust18 [17]
3 years ago
13

Steam at 1 MPa, 300 C flows through a 30 cm diameter pipe with an average velocity of 10 m/s. The mass flow rate of this steam i

s: (d) 3.78 kg/s (a) 0.731 kg/s(b) 2.74 kg/s (c) 3.18 kg/s
Engineering
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

\dot m = 2.74 kg/s

Explanation:

given data:

pressure 1 MPa

diameter of pipe  =  30 cm

average velocity = 10 m/s

area of pipe= \frac[\pi}{4}d^2

                 = \frac{\pi}{4} 0.3^2

A = 0.070 m2

WE KNOW THAT mass flow rate is given as

\dot m = \rho A v

for pressure 1 MPa, the density of steam is = 4.068 kg/m3

therefore we have

\dot m = 4.068 * 0.070* 10

\dot m = 2.74 kg/s

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Exit temperature = 32 °C

Explanation:

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Initial Pressure;P1 = 100 KPa

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R = 500 J/kg.K = 0.5 Kj/Kg.k

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