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faust18 [17]
3 years ago
13

Steam at 1 MPa, 300 C flows through a 30 cm diameter pipe with an average velocity of 10 m/s. The mass flow rate of this steam i

s: (d) 3.78 kg/s (a) 0.731 kg/s(b) 2.74 kg/s (c) 3.18 kg/s
Engineering
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

\dot m = 2.74 kg/s

Explanation:

given data:

pressure 1 MPa

diameter of pipe  =  30 cm

average velocity = 10 m/s

area of pipe= \frac[\pi}{4}d^2

                 = \frac{\pi}{4} 0.3^2

A = 0.070 m2

WE KNOW THAT mass flow rate is given as

\dot m = \rho A v

for pressure 1 MPa, the density of steam is = 4.068 kg/m3

therefore we have

\dot m = 4.068 * 0.070* 10

\dot m = 2.74 kg/s

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pashok25 [27]

Forces exerted by the jet on the plate is=3976N

<h3>How to calculate forces exerted by the jet on the plate?</h3>

A force is an effect that can change the motion of an object. A force can generate an object with mass to change its velocity, i.e., to accelerate. Force can also be explained intuitively as a push or a pull. A force has both volume and direction, making it a vector amount.

A jet of water 75m in diameter

velocity = 30m/s

The forces exerted by the jet on the plate is

F=1000×44178×10^-3×30²

=3976N

the jet on the plate work done by Is zero .

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5 0
2 years ago
Carbon dioxide at a temperature of 0oC and a pressure of 600 kPa (abs) flows through a horizontal 40-mm- diameter pipe with an a
rusak2 [61]

Answer:

f = 0.04042

Explanation:

temperature = 0°C = 273k

p = 600 Kpa

d = 40 millemeter

e = 10 m

change in  P = 235 N/m²

μ = 2m/s

R = 188.9 Nm/kgk

we solve this using this formula;

P = ρcos*R*T

we put in the values into this equation

600x10³ = ρcos * 188.9 * 273

600000 = ρcos51569.7

ρcos = 600000/51569.7

=11.63

from here we find the head loss due to friction

Δp/pg = feμ²/2D

235/11.63 = f*10*4/2*40x10⁻³

20.21 = 40f/0.08

20.21*0.08 = 40f

1.6168 = 40f

divide through by 40

f = 0.04042

5 0
3 years ago
O local utilizado pelos grandes avioes para descolar e aterrar
IRISSAK [1]
Decolagem e pouso


espero que ajude
7 0
3 years ago
The specific gravity of a substance that has mass of 10 kg and occupies a volume of 0.02 m^3 is a) 0.5 b) 1.5 c) 2.5 d) 3.5 e) n
zhuklara [117]

Answer:

Specific gravity is 0.5 so option (a) is correct option

Explanation:

We have given mass of substance m =10 kg

Volume V=0.02m^3

Density of substance is given by Density\ d=\frac{mass}{volume}=\frac{10}{0.02}=500kg/m^3

Specific gravity is given by specific\ gravity=\frac{density\ of\ substance}{density\ f\ water}=\frac{500}{1000}=0.5

So option (a) is correct option

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3 years ago
A master stud pattern is laid out somewhat<br> like a?
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••• like a story pole but has information for only one portion of the wall. system. methods and materials of construction.

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2 years ago
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