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RoseWind [281]
3 years ago
5

While on vacation in the tropical Bahamas, Suzy decides to try out a water jet pack. She places the jet pack on her back (like y

ou would wear a backpack), pushes the buttons in her hands, and water comes shooting out of the bottom of the jetpack, exerting a force on the ocean below. Why does Suzy fly up into the air? In your answer, be sure to state which of Newton's laws of motion this pertains to, describe this law, and explain how it causes Suzy to fly up into the sky.
Physics
1 answer:
Veronika [31]3 years ago
5 0

Answer:

-Suzy flies up into the sky because of the upward force on the jetpack.

-Newton's third law of motion can be ascribed to this.

Explanation:

We know that in momentum, Force is described as the rate of change of momentum. Thus, for us to understand the forces, we will need to establish how the momentum of the water changes.

Suppose the mass flow rate of the water is denoted as M kg/sec and the upward velocity is denoted as v_u.

Now, since water is lying stationary at the sea, the initial momentum of the water will be zero. If every second the boat pumps upwards with mass flow rate M at velocity vu, the momentum per second would be;

Δp = F_water = Mv_u

Now, from Newton's third law the boat/pump would experience a downwards force with the formula:

F_boat = −Mv_u

Furthermore at the jetpack, the water does a reverse turn in direction and is now again directed back down at a different velocity v_d. Therefore the final momentum per second is Mv_d and therefore change in momentum is now;

Δp = M(v_d - v_u)

The velocity v_d will be negative since the boat/pump would experience a downwards force. Thus, the force on the water will be downwards and F_water ≤ 0 .

We will finally use Newton's third law to conclude that the upward force on the jetpack will be;

F_jetpack = M(v_u - v_d)

Thus upward force is what makes Suzy to fly up in the sky.

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During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t
tia_tia [17]

1.A) 4.9 m  

AL2006 Ace

The instant it was dropped, the ball had zero speed.


After falling for 1 second, its speed was 9.8 m/s straight down (gravity).


Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.


Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.


ANYTHING you drop does that, if air resistance doesn't hold it back.


Read more on Brainly.com - brainly.com/question/11776597#readmore

2 idk sorry

5 0
3 years ago
Read 2 more answers
you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k
alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}

→ v_{p}=150 km/h ,  v_{w}=50 km/h

→ v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11 km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is tan^{-1}\frac{50}{150}=18.4°

The direction of the velocity is 18.4° west of south

<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>

8 0
3 years ago
PLEASE HELP!
SashulF [63]

Answer:

They gon' hate me regardless, that's why I do what I do (what I do)

See me in person i'm flawless (I'm flawless girl), i might just snatch up your dude (hahahaha)

Explanation:

i just want to be....appreciated

3 0
3 years ago
If the angle of reflection is 25 degrees, the angle of incidence is
natali 33 [55]

Answer:

25 degrees

Explanation:

The angle of incidence equals the angle of reflection

7 0
3 years ago
A circular sign has a diameter of 40 cm and is subjected to normal winds up to 150 km/h at 10°C and 100 kPa. Determine the drag
Marat540 [252]

Answer:

147.7 N

221.55 Nm

Explanation:

P = Pressure = 100000 Pa

R_s = Mass-specific gas constant = 287.015 J/kg k

T = Temperature = 10+273 = 283 K

C = Drag coefficient = 1.1

A = Area

r = Radius = 0.2 m

v = Speed of wind = \frac{150}{3.6}\ m/s

L = Length of pole

Density

\rho=\frac{P}{R_sT}\\\Rightarrow \rho=\frac{100000}{287.058\times 283}\\\Rightarrow \rho=1.2309\ kg/m^3

Drag force

F=\frac{1}{2}\rho CAv^2\\\Rightarrow F=\frac{1}{2}\times 1.2309\times 1.1\times \left(\pi \times 0.2^2\right)\times \left(\frac{150}{3.6}\right)^2\\\Rightarrow F=147.7\ N

Force on the circular sign is 147.7 N

M=F\times L\\\Rightarrow M=147.7\times 1.5\\\Rightarrow M=221.55\ Nm

Bending moment at the bottom of the pole is 221.55 Nm

6 0
3 years ago
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