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ale4655 [162]
3 years ago
5

What is transferred by a force moving an object through a distance?

Physics
2 answers:
Komok [63]3 years ago
7 0
<span>When you apply force to move an object at a distance, you are applying work. And work is energy in transit. The answer is letter D. For example, you see a cart at a distance. You observe that it is not moving. You want to transfer it to your backyard. You apply force to the cart and observed that the cart is not at the same position as it was before. You are applying work to the cart by transferring your energy to it.</span>
Anvisha [2.4K]3 years ago
6 0

Answer:

When you apply force to move an object at a distance, you are applying work. And work is energy in transit. The answer is letter D. For example, you see a cart at a distance. You observe that it is not moving. You want to transfer it to your backyard. You apply force to the cart and observed that the cart is not at the same position as it was before. You are applying work to the cart by transferring your energy to it.

Explanation:

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In the case of the <u>Earth</u>, in which  <u>the gravitational field is considered constant</u>, the value of the gravitational potential energy U_{p} will be:

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konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

Therefore, the mass of the body is 0.02 kg.

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