<span>If "m" balls are thrown per second, the time taken for a ball to reach its maximum height will be 1/m seconds. How to get this? See that the next ball is thrown only when the previous ball reaches its maximum height. If 'm' balls were thrown in 1 second this means that each ball was attaining its maximum ht in 1/m seconds.
This was the main part. Now we can proceed to find maximum height in 2 ways-
a)
We know for upward journey ,
t=1/m
a=-g
v=u-gt
final velocity ,v = 0 (at highest point)
u
=gt = g/m
Now we can apply
h=ut-1/2 gt^2
Putting the values of u,t, we will get
h= g/2m^2
b)
The second method uses a trick that time taken to reach the maximum ht is same as time taken to fall down.
So, we will now consider the downward journey of ball which also takes 1/m seconds
We apply
h=ut+1/2gt^2
Here u=0 ,t=1/m
We will again get ,
h=g/2m^2</span>
True hope this helps, <span>Nictheuse !</span>
Explanation:
Since compasses work by pointing along magnetic field lines, this means that there must be a magnetic field near the wire through which the current is flowing.
Answer:
North of west
Explanation:
Given
40,000-ton luxury line traveling 20 knots towards west and
60,000 ton freighter traveling towards North with 10 knots
suppose v is the common velocity after collision
conserving momentum in west direction
suppose the final velocity makes \theta angle with x axis
Conserving Momentum in North direction
divide 1 and 2
so search in the area North of west to find the ship
