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4 years ago

13

In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ball changed t

o -0.4 meter/second. The collision takes 0.2 seconds to occur. What’s the acceleration of the ball during the collision? Use .

1 answer:

DENIUS [597]4 years ago

6 0

Answer:

-5 m/s²

Explanation:

Acceleration = change in velocity / change in time

a = (v − v₀) / (t − t₀)

a = (-0.4 m/s − 0.6 m/s) / 0.2 s

a = -5 m/s²

The ball decelerates at a rate of -5 m/s².

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A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als

iragen [17]

The voltage provided by the power supply = 20 V

<h3>Resistors in series </h3>

The Voltage across resistors in series in a circuit is equal to the sum of the voltage drops across each resistor.

Therefore for two resistors in series the total voltage provided by the power supply is equivalent to the summation of the voltage drops acroos each resistor ( i.e 10 V + 10 V = 20 V )

Hence we can conclude that the voltage provided by the power supply is 20 V

Learn more about reisitors in series : brainly.com/question/11657573

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2 years ago

This question is typical on some driver’s license exams: A car moving at 45 km/h skids 15 m with locked brakes. How far will the

sergiy2304 [10]

from kinematics equation if we know that final speed is ZERO and initial speed is given that due to constant deceleration the object will stop in some distance "d" and this distance can be calculated by kinematics

$v_f^2 - v_i^2 = 2 a d$

$0 - v^2 = 2(a)d$

here acceleration due to friction will be same at all different speed

so for 45 km/h speed the distance of stop is 15 m

while at other speed 112.5 km/h the distance will be unknown

now we will have

$0 - 45^2 = 2(a)15$

$0 - 112.5^2 = 2(a)d$

now divide above two equations

$\frac{45^2}{112.5^2} = \frac{15}{d}$

$d = 93.75 m$

So it will stop in distance 93.75 m

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3 years ago

Objects appear different in size and shape in a container of water due to

o-na [289]

Answer:

A. refraction of light waves

Explanation:

Refraction happens when light travels from one medium to another and changes speed and bends. This also causes objects to look different sizes and shapes when they are submerged in water.

5 0

3 years ago

Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30

vekshin1

66.7 Watts

Explanation:

Let $R_{1}=1.0$ ohms, $R_{2}=3.0$ ohms and $R_{3}=6.0\:$ ohms. Since $R_{2}$ and $R_{3}$ are in parallel, their combined resistance $R_{23}$ is given by

$\dfrac{1}{R_{23}}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}$

or

$R_{23}=\dfrac{R_{2}R_{3}}{R_{2}+ R_{3}}=2.0\:ohms$

The total current flowing through the circuit <em>I</em> is given

$I=\dfrac{V_{s}}{R_{Total}}$

where

$R_{Total}=R_{1}+R_{23}= 3.0\:ohms$

Therefore, the total current through the circuit is

$I=\dfrac{30\:V}{3.0\:ohms}=10\:A$

In order to find the voltage drop across the 6-ohm resistor, we first need to find the voltage drop across the 1-ohm resistor $V_{1}$ :

$V_{1}=(10\:A)(1.0\:ohms)=10\:V$

This means that voltage drop across the 6-ohm resistor $V_{3}$ is 20 V. The power dissipated <em>P</em> by the 6-ohm resitor is given by

$P=I^{2}R_{3}= \dfrac{V^{2}}{R_{3}}=\dfrac{(20\:V)^{2}}{6\:ohms}= 66.7 W$

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3 years ago

A spring with an unstrained length of 0.074 m and a spring constant of 2.4 N/m hangs vertically downward from the ceiling. A uni

-BARSIC- [3]

Mg + kx = QE , k = 2.4 x = 0.074-0.059 , Q = 6.6C m = given solve

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3 years ago