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Maurinko [17]
2 years ago
12

A sled starts from rest,

Physics
1 answer:
Scorpion4ik [409]2 years ago
6 0

Answer:

The acceleration of the sled is 4.6\ m/s^2.

Explanation:

It is given that,

Initial speed of sled is 0 because it was at rest.

It is placed at an angle of 28° on a frictionless hill.

We need to find the acceleration of the sled. It is placed at an incline. It means that the acceleration of the sled is given by :

a=g\sin\theta\\\\a=9.8\times \sin(28)\\\\a=4.6\ m/s^2

So, the acceleration of the sled is 4.6\ m/s^2.

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A shot putter heaves a 7.26kg shot with final velocity of 7.50m/s what is kinetic energy?
ivanzaharov [21]

Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

8 0
2 years ago
What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this
Finger [1]

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as N_2, is given by

U=\frac{5}{2}nRT

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

T=253^{\circ} + 273 = 526 K (absolute temperature)

Substituting, we find:

U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J

Learn more about ideal gases:

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6 0
3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

6 0
2 years ago
The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?​
kompoz [17]

Answer:

1500 per second.

Explanation:

vibrations = 1.5 kilohertz

1.5×1000=1500

the answer is 1500 per second.

6 0
2 years ago
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A planet has a period of revolution about the Sun equal to and a mean distance from the Sun equal to R .T^2 varies directly as _
shutvik [7]

T² caries directly as R³ .

This is Kepler's 3rd law of planetary motion .
4 0
2 years ago
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