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Elanso [62]
4 years ago
5

Would the weight density of water be different on the moon than it is on earth?

Physics
1 answer:
-BARSIC- [3]4 years ago
6 0
No the weight would be changed due to the different gravity. The density won't change though. This is due to the density is related to the hydrogen bond between water
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Which statement did John Dalton make about atoms?
Roman55 [17]

Answer:

B). the atom is made up of smaller particles

8 0
3 years ago
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Suppose a 350-g kookaburra (a large kingfisher bird) picks up a 75-g snake and raises it 2.5 m from the ground to a branch. (a)
mafiozo [28]

(a) The work done by the bird to raise the snake on the branch is equal to the product between the weight of the snake and the height of the branch above the ground:

W_1 = mg h

where m=75 g=0.075 kg is the mass of the snake and h=2.5 m is the height of the branch with respect to the ground. Substituting numbers into the equation, we find

W_1 = (0.075 kg)(9.81 m/s^2)(2.5 m)=1.84 J


(b) The work the bird did to raise its own centre of mass from the ground to the branch is equal to the product between the bird's weight and the height of the branch:

W_2 = mgh

where m=350 g=0.35 kg is the mass of the bird. Substituting numbers into the equation, we find

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6 0
3 years ago
. A 1.50kg mass on a spring has a displacement as a function of time given by the equation: x(t) = (7.40cm)cos[(4.16s-1)t – 2.42
rusak2 [61]

Answer:

Solution:

we have given the equation of motion is x(t)=8sint [where t in seconds and x in centimeter]

Position, velocity and acceleration are all based on the equation of motion.

The equation represents the position.  The first derivative gives the velocity and the 2nd derivative gives the acceleration.

x(t)=8sint

x'(t)=8cost

x"(t)=-8sint

now at time t=2pi/3,

position, x(t)=8sin(2pi/3)=4*squart(3)cm.

velocity, x'(t)=8cos(2pi/3)==4cm/s

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so at present the direction is in y-axis.

5 0
3 years ago
Need help with these physic questions!
gtnhenbr [62]

Explanation:

4.

Given: Δd = 4 + 2 + 1 = 7km, Δt = 32 + 22 + 16 = 70mins

Required: V

Equation: V = Δd/Δt

Solution: V = 7/70

                  = 0.1km/min

6 0
3 years ago
1. A truck of mass 3120 kg is accelerated from rest to a speed of 22.1 m/s. How much work was done on the truck to achieve that
Goryan [66]

Answer:

.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J

Explanation:

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