Answer:
given,
initial velocity = 11.5 m/s
acceleration = 0.5 m/s²
time = 7 s
a) using equation of motion
v = u + a t
v = 11.5 + 0.5 × 7
v = 15 m/s
b)
s = 92.75 m
distance traveled by racer with final velocity
d = 300 - 92.75
= 207.25 m
time spend to travel 207.25
t = 13.82 s
total time spent to travel 300m
t = 7 + 13.82
t = 20.82 s
time required to travel 300 m with initial velocity
= 26.09 s
time saved due to acceleration
t = 26.09 - 20.82 = 5.27 s
c) second racer is 5 m apart from the first one
distance traveled by the second racer till first one finishes the race
distance behind the leader
d = 300 -5 -245.676 = 49.34 m
time behind the winner