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yKpoI14uk [10]
3 years ago
8

Rachel and Hugo sorted 236 crayons into boxes for a local arts project. Each box had 10 crayons. How many crayons were left over

?
Mathematics
2 answers:
Kryger [21]3 years ago
8 0
This is a simple division problem. Since there are 236 crayons, in groups of ten, there will be 6 left over because there is a 6 in the ones place. 
Mariulka [41]3 years ago
7 0
<em>If the started off with 236 crayons into the boxes and each box had 10 crayons then you divide 236 and 10 which equals 23.6 rounded to 24 but i have no idea if that would be the correct answer</em>
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Lillian has nickels, dimes, and quarters in her coin purse. She has 3 fewer dimes than quarters, and 3 times as many nickels as
Reil [10]

Answer:

18 nickels, 6 dimes, and 9 quarters

Step-by-step explanation:

nickels dimes and quarters

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x+y+z=33

y+3=z

3y=x

3y+y+y+3=33

5y+3=33

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z=9

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Hope this helps plz hit the crown :D

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Plz give me explanation how to solve
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4 0
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Which number is rational?<br><br> A.π B.0.36458121… C.0.777... D. √5
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4 0
3 years ago
Read 2 more answers
Need help please anyone?
poizon [28]

Ok so for part a we're going to use substitution, since both equations have y alone.

Step 1: Use substitution

y = x - 1    y = -x + 3

x - 1 = -x + 3

If you think about it, this makes sense. You're looking for the point where they intersect, and you know that the y coordinate for that point will be the same in both equations. Therefore, we can set the rest of the equations equal to each other. Now we just need to simplify.

Step 2: add x to each side

x - 1 + x = -x + 3 + x

The x's on the right cancel out so we get:

2x - 1 = 3

Step 4: Add 1 to each side

2x - 1 + 1 = 3 + 1

2x = 4

Step 5: Divide both sides by 2

2x/2 = 4/2

x = 2

Step 6: Plug this x value back into one of the original equations to find the y coordinate

y = x - 1

y = 2 - 1

y = 1

Therefore your answer to part a is (2,1)


I've graphed the solution and attached it. It shouldn't be too hard to replicate - just draw both lines and they should intersect at (2,1)


Hope that helps! If you need clarification or anything please feel free to ask :)

4 0
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