Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is
where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as
Now, we can say that m>n because m and n are positive integers.
For n=1,
19 is not divisible by 5 so m is not an integer for n=1.
For n=2,
The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is
Therefore the smallest positive integer solution to the given system of congruences is 30.
Answer:
Hello,
in order to simplify, i have taken the inverses functions
Step-by-step explanation:
![\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%20%7B%28-2x%5E2-x%2B1%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B%5Cfrac%7B-2x%5E3%7D%7B3%7D%20-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%2Bx%5D%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-2-3%2B12%7D%7B24%7D%20-%5Cdfrac%7B-5%7D%7B6%7D%20%5C%5C%5C%5C%5Cboxed%7B%3D%5Cdfrac%7B9%7D%7B8%7D%20%3D1.25%7D%5C%5C)
Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
Most times, it’s good to talk to your teacher for help. I think it would be a good idea to ask your parent, sibling or any adult for help. Sometimes you think harder than you should so relax and try reading the question again. I hope you figure this out! Good luck!
A rectangle is a two-dimensional shape with two sets of equal, parallel sides. These dimensions are the length (L) and the width (W). The formula for the rectangle's area is the product of the two dimensions. The formula for perimeter is
P = 2L + 2W
Since
A = LW = 64
W = 64/L
Substituting to the formula for perimeter would be,
P = 2L + 2(64/L)
P = 2L + 128/L
