Question

Write the equilibrium constant expression for this reaction: 3h (aq) po−34 (aq) → h3po4 (aq)

Answer 1

Answer: $K=\frac{[H_3PO_4]}{[H^+]^3[PO_4^{3-}]}$

Explanation:

Equilibrium constant is the ratio of product of concentration of products to the product of concentration of reactants each term raise to their stochiometric coefficients.

Thus for the reaction:

$3H^+(aq)+PO_4^{3-}(aq)\rightarrow H_3PO_4(aq)$

$K=\frac{[H_3PO_4]}{[H^+]^3[PO_4^{3-}]}$