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gizmo_the_mogwai [7]
4 years ago
13

Write the equilibrium constant expression for this reaction: 3h (aq) po−34 (aq) → h3po4 (aq)

Chemistry
1 answer:
dybincka [34]4 years ago
4 0

Answer: K=\frac{[H_3PO_4]}{[H^+]^3[PO_4^{3-}]}

Explanation:

Equilibrium constant is the ratio of product of concentration of products to the product of concentration of reactants each term raise to their stochiometric coefficients.

Thus for the reaction:

3H^+(aq)+PO_4^{3-}(aq)\rightarrow H_3PO_4(aq)

K=\frac{[H_3PO_4]}{[H^+]^3[PO_4^{3-}]}

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The pressure of a 5.0 L sample of gas changes from 3.0 atm to 10.0 atm while the temperature remains constant. What is the gas’s
lina2011 [118]

Answer:

<h2>The answer is 1.5 L</h2>

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8 0
3 years ago
What is the hydroxide [OH-] concentration of a solution that has a pOH of 4.90? 14 14 1.26 x10-5 1.26 x10, -5 9.1 9.1 7.94 x 104
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Answer:

The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):

pOH= -log [OH-]

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4.90= -log [OH-]

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