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2 years ago

9

It says draw a ring around all the objects that will be attracted to a magnet the one there are : a 2p coin,cobalt,an aluminium

can,a lead piping,nickel and sir galahad’s suit of steel amour what should i ring??

1 answer:

Katen [24]2 years ago

5 0

Answer: do

Explanation:

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How many molecules are in 1.75 moles of Caco3?

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Answer:

1.054 x 10²⁴ molecules

Explanation:

In order to convert moles <em>of any given substance</em> into a number of molecules, we need to use <em>Avogadro's number</em>, which states the number of molecules -or atoms, in the case of elements- present in one mol:

In one mol there are 6.023x10²³ molecules.

We now <u>convert 1.75 moles into molecules</u>:

1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ molecules

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If gas is $4.00/gal, how much does it cost to travel from Portland, Maine, to Orlando, Florida (a distance of 1,500 mi)? Give yo

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3 years ago

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marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

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3 years ago