Answer:
Ans. C. physical change
Explanation:
Physical: boiling and melting are physical changes. When water boils no bonds are broken or formed
The correct answer would be false
Hope this helped! ☺
We frequently observe kids playing with polythene bags filled with water that have little holes drilled into them at various locations so they can sprinkle water on other kids. Through this experiment, we can say that pressure acts in all directions in liquids.
<h3>Liquid's pressure</h3>
Since both liquids and gases may flow, they are both referred to as fluids. Fluids under rest pressure behave uniformly in all directions.
Weather forecasts can be made using barometers. They track the evolution of atmospheric pressure throughout time.
On weather forecast maps, pressure variations appear as an isobar pattern. Predictions are made using these changes in pressure, and they are fairly accurate when combined with wind observations.
<h3>Pressure and depth in liquids</h3>
As you go away from a liquid's surface, pressure rises. for instance: A bucket has three holes that are all the same size. Since there is more pressure at the bucket's bottom, the water spills out more forcefully. Dams are thicker at the bottom for this reason.
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Answer:
The density increases.
Explanation:
As you go deeper in depth, pressure increases. Density = mass/volume. The layers beneath us due to pressure get packed to the point of being very dense.
Answer:
hello your question is incomplete attached below is the complete question
a) 0.12 M
b) Ka = 3.0 * 10^-7
c) Alizarin Yellow R
Explanation:
<u>A) Determine the concentration of the unknown acid</u>
The PH of the unknown acid before addition of NaOH is ; 3.72 ( weak acid )
First determine the moles of of NaOH
= molarity * volume
= 0.10 M * 30.0 ML = 0.0030 mol
at equivalence point
moles of NaOH = moles of unknown acid = 0.0030 mol
volume of unknown acid = 25.0 mL
Next calculate the concentration of the Acid ( HA )
= moles / volume
= 0.0030 mol / 25.0 mL
= 0.12 M
<u>b) Determine the Ka of the unknown acid </u>
attached below is the detailed solution
Ka = 3.0 * 10^-7
c) The indicator that would be a good choice to use in the titration of this acid with NaOH is ; Alizarin Yellow R . this is because the titration is between a strong base and a weak acid.
