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patriot [66]
3 years ago
13

The paths in which electrons travel are called what ovals ,paths,circles,orbitals

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0
The paths in which electrons travel are called orbitals.

Virty [35]3 years ago
3 0

They are called orbitals

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Physical Science Structures and Properties of Matter Portfolio
daser333 [38]

Answer:

true

Explanation:

8 0
3 years ago
What do calcium chloride, sodium carbonate, calcium carbonate, and potassium carbonate all have in common? (other than they reac
VARVARA [1.3K]

Answer:

the all dissolve in water

Explanation:

7 0
3 years ago
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Which of these statements explains the difference between nuclear binding energy and the strong nuclear force? Check all that ap
vitfil [10]

Answer:Nuclear binding energy is the energy needed to separate nuclear particles

The strong nuclear force holds an atom’s protons and neutrons together

Nuclear binding energy can be calculated using E=mc2

Explanation:

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3 years ago
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What gives the gem amethyst its purplish color?
Semenov [28]
The question is asking us to determine what gives the Amethyst its purplish color. Amethyst colors range from light to dark purple. The most highly regarded are the transparent deep purple colors. Amethyst ( chemical formula: Si O2 ) is the purple variety of the mineral Quartz.The pure Quartz is often colorless. Amethyst gets its purplish color because of the presence of Iron ( Fe ) and other impurities in the gem. Answer: C. Iron.<span /><span />
5 0
3 years ago
1.15.7 cm3 of HCl completely neutralised 25 cm3 of LiOH. The HCl was 2 mol/dm3.The equation is :
Whitepunk [10]

Answer:

C₂ = 1.26 mol/dm³

Explanation:

Given data:

Volume of HCl =V₁ =  15.7 cm³

Volume of LiOH = V₂ =  25 cm³

Concentration of HCl =C₁ = 2 mol/dm³

Concentration of LiOH =C₂=  ?

Solution:

Chemical equation:

LiOH + HCl    →     LiCl + H₂O

Formula:

C₁V₁   = C₂V₂

by putting values,

15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³

C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³

C₂ = 31.4 cm₃.mol/dm³ / 25 cm³

C₂ = 1.26 mol/dm³

8 0
3 years ago
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