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3 years ago

What is the slope of the line that passes thru (7,2) and (9,6)?

1 answer:

8 0

Hey there Hopire :)
To solve this, we'll use the slope given two points formula. Here it is:

y2-y1/x2-x1

Plug in the values.

6-2/9-7 =

4/2 =

2

Therefore, the slope is two, meaning 2/1 because slope is rise/run. That means that for every two you go up, you go one to the right because it's a positive slope- left for negatives.

Hope this helped!

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Beth is taking out a loan to purchase a new home. She is financing $50,000 for 25 years at an interest rate of 14.25%. What is h

kozerog [31]

The present value (PV) of a loan for n years at r% compounded t times a year where there is equal P periodic payments is given by:

$PV=P\left( \frac{1-\left(1+ \frac{r}{t} \left)^{-nt}}{ \frac{r}{t} } \right)$

Given that Beth is taking out a loan of PV = $50,000 to purchase a new home for n = 25 years at an interest rate of r = 14.25%. Since she is making the payment monthly, t = 12.

Her monthly payment is given by:

$50,000=P\left( \frac{1-\left(1+ \frac{0.1425}{12} \right)^{-25\times12}}{ \frac{0.1425}{12} } \right) \\ \\ =P\left( \frac{1-(1+0.011875)^{-300}}{ 0.011875 } \right)=P\left( \frac{1-(1.011875)^{-300}}{ 0.011875 } \right) \\ \\ =P\left( \frac{1-0.028969}{ 0.011875 } \right)=P\left( \frac{0.971031}{ 0.011875 } \right)=81.770994P \\ \\ \therefore P= \frac{50,000}{81.770994} =\$611.46$

Therefore, her monthly payment is about $611.50

3 0

3 years ago

The Neolithic Revolution

Amanda [17]

The Neolithic Revolution allowed people to live in permanent settlements.

Explanation:

The Neolithic Revolution is the phase of transition in which many of the human cultures in the world shifted their lifestyle to permanent settlement and agriculture from hunting and gathering.

This era is also named as First Agricultural Revolution or Neolithic Demographic Transition. The agricultural practices led the cultures to develop the knowledge of domestication of animals and they began to observe and experiment with the plants (to learn or know how they grow and develop).

Neolithic period is named as revolution because this period changed the way of life of most of the communities. This first occurred in so-called "Fertile Crescent" or Mesopotamia (modern Iraq).

6 0

3 years ago

Read 2 more answers

Mr. Beber feeds his dog 1/5 of a cup of dog food each day. How long will 9 cups of dog food last?

m_a_m_a [10]

Answer:

45 days

Step-by-step explanation:

Step 1: Determine how long it will last

(9 cups) * (5 days / cup)

45 days

Answer: 45 days

5 0

2 years ago

The area is no more than 40 square feet. Write and solve an inequality that represents the value of x

Anna35 [415]

Answer:

well its a triangle so

40 divide by 20 is 2

but you have to mutiply that 2 by 2

Step-by-step explanation:

3 0

2 years ago

Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic

nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

(b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.

For the class 1-5, RF = 12/20 = 0.6.

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes) F RF CF RCF

1-5 12 0.60 12 0.60

6-10 3 0.15 15 0.75

11-15 2 0.10 17 0.85

16-20 1 0.05 18 0.90

21-25 1 0.05 19 0.95

26-30 0 0.00 19 0.95

31-34 1 0.05 20 1

Total 20

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0

3 years ago