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3 years ago

How to find the determinant of a 3x3 matrix?

1 answer:

4 0

This is how

1. Write your 3 x 3 matrix. More ↓
2. Choose a single row or column. ↓
3. Cross out the row and column of your first element. ↓
4. Find the determinant of the 2 x 2 matrix. ↓
5. Multiply the answer by your chosen element. ↓
6. Determine the sign of your answer. ↓
7. Repeat this process for the second element in your reference row or column. ↓
8. Repeat with the third element. ↓
9. Add your three results together. ↓

Hope this helps!

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Help with simple interest rate P=$18,000, r= 7.5%, t=18 months

n200080 [17]

=2025
change 18months to years=1.5 years then you use the formula
PRT÷100
$18000 \times 7.5 \times 1.5 = 202500 \div 100 = 2025$

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4 years ago

A parallelogram has coordinates A(1, 1), B(5, 4), C(7, 1), and D(3, -2). What are the coordinates of parallelogram A′B′C′D′ afte

andrezito [222]

Answer:

C I think

Step-by-step explanation:

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3 years ago

Consider the vector x: x <- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Opti

Nookie1986 [14]

Completed Question

Outputs to be matched to the functions are:

1,2,3,4,5
1,5,3,2,4
1, 4, 3, 5, 2
2, 18, 27, 43, 96

Answer:

sort(x): 2, 18, 27, 43, 96
order(x): 1, 5, 3, 2, 4
rank(x) : 1, 4, 3, 5, 2
none of these : 1, 2, 3, 4, 5

Step-by-step explanation:

Given the vector x: x <- c(2, 43, 27, 96, 18)

Sort

In R, the sort(x) function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.

Therefore, the output that matches the sort function is:

sort(x): 2, 18, 27, 43, 96

Rank

The rank function returns a vector with the "rank" of each value.

x <- c(2, 43, 27, 96, 18)

2 has a rank of 1
43 has a rank of 4
27 has a rank of 3
96 has a rank of 5
18 has a rank of 2

Therefore, the output of rank(x) is: 1, 4, 3, 5, 2

Order

When the function is sorted, the order function gives the previous location of each of the element of the vector.

Using the sort(x) function, we obtain: 2, 18, 27, 43, 96

In the vector: x <- c(2, 43, 27, 96, 18)

2 was in the 1st position
18 was in the 5th position
27 was in the 3rd position
43 was in the 2nd position
96 was in the 4th position

Therefore, the output of order(x) is: 1, 5, 3, 2, 4

7 0

3 years ago

Show why x−3 is a factor of m(x)=x3−x2−5x−3. Justify your answer. You can show this using remainder theorem, long division, synt

Marat540 [252]

The factors of a polynomial function are the zeros of the function

It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3

<h3>How to show why the x - 3 is a factor</h3>

The function is given as:

m(x) = x^3 - x^2 - 5x - 3

The factor is given as:

x - 3

Set the factor to 0

x - 3 = 0

Solve for x

x = 3

Substitute 3 for x in the function

m(3) = 3^3 - 3^2 - 5(3) - 3

Evaluate

m(3) =0

Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3