Answer:
P₁- P₂ = 91.1 10³ Pa
Explanation:
For this exercise we will use Bernoulli's equation, where point 1 is at the bottom of the house and point 2 on the second floor
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
P1-P2 = ½ ρ (v₂² - v₁²) + ρ g (y₂-y₁)
In the exercise they give us the speeds and the height of the turbid, so we can calculate the pressure difference
For heights let's set a reference system on the ground floor of the house, so we have 5m for the second floor and an entrance at -2m
P₁-P₂ = ½ 1.0 10³ (7² - 2²) + 1.0 10³ 9.8 (5 + 2)
P₁-P₂ = 22.5 10³ + 68.6 10³
P₁- P₂ = 91.1 10³ Pa
To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:
We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,
Where
V = Velocity
A = Cross-sectional Area
Our values are given as
Since there is continuity we have now that,
Therefore the speed of the water's house supply line is 0.347m/s
For displacement apply Pythagorean theorem
Quartz, gold and calcite are examples of minerals, coal is a fossil fuel
We already know the formula for finding the energy of a photon with this wavelength as:
<span>E = ħc / λ
</span>The information's that we already know are:
h = Plancks constant
= <span>6.626x10^-34 Js
c = light speed
= </span><span> 2.999x10^8 m/s
</span><span>λ = Wavelength of the light as given in the question
</span> = <span>670.8x10^-9 m
E = amount of energy
Then
E = (</span>6.626x10^-34) * (2.999x10^8)/ (<span>670.8x10^-9)
= </span><span>2.962x10^-19 J</span>
