Adding energy or increasing the speed of the particles at very low pressure in a solid would cause

If 100 grams of vinegar and 5 grams of baking soda are poured in a container, a small amount of gas will be produced. What will

Anit [1.1K]

It will be a little bit less because of evaporation i learned that in third grade and your in high school that is sad

5 0

3 years ago

A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.

bekas [8.4K]

Answer with Explanation:

We are given that

Mass=80 kg

Radius,r=10 m

Speed,v=6.1 m/s

a.Time period,T= $\frac{2\pi r}{v}=\frac{2\pi\times 10}{6.1}=10.3 s$

b. $F_N=mg-\frac{mv^2}{r}$

Substitute the values

$F_N=80\times 9.8-\frac{80\times(6.1)^2}{10}=486 N$

c. $F_N=mg+\frac{mv^2}{r}$

Substitute the values

$F_N=80\times 9.8+\frac{80\times (6.1)^2}{10}=1081.7 N$

7 0

3 years ago

A block slides down a rough ramp with a 30-degree incline as shown.

In-s [12.5K]

Answer:

Image 4 ?

Explanation:

5 0

3 years ago

An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull

puteri [66]

Answer:

$\mu=0.0049Kg/m$

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

$f_n=\frac{nv}{2L}$

Where $L$ is the length of the string and $v$ the velocity of propagation. Use this expression to find the value of $v$ .

$f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s$

The velocity of propagation is given by the expression:

$v=\sqrt{\frac{T}{\mu }$

Where $\mu$ is the desirable variable of the problem, the linear mass density, and $T$ is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

$T=W=mg=(5)(9.81)=49.05N$

With the value of the tension and the velocity you can find the mass density:

$v=\sqrt{\frac{T}{\mu}$

$v^2=\frac{T}{\mu}\\ \mu=\frac{T}{v^2} =\frac{49.05}{(100)^2} =\frac{49.05}{10000} =0.0049Kg/m$

6 0

2 years ago

A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb

densk [106]

Voltage=V=120V
Power=P=60W

Current=I

$\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A$

8 0

2 years ago