Question

the fireman wishes to direct the flow of water from his hose to the fire at b. determine two possible angles u1 and u2 at which this can be done. water flows from the hose at va

Answer 1

The two possible angles obtained by using the qudratic equation are;

θ$_{1}$ = 15.10° and θ2 = 73.51°

Given, speed of water = $v_{A}$ = 50ft/s

For the motion along x direction, time period can be calculated as follows:

$s_{x} = (v_{A}) _x_{} } t$

35 = (50 × cosθ) t

t = 0.64 / cosθ

For the motion in y direction, an equation can be obtained as follows:

$s_{y} = (v_{A})_{y} t +\frac{1}{2} (a_{y} )t^{2}$

$s_{y} = (-v_{A}$$sin$θ) $} t +\frac{1}{2} (a_{y} )t^{2}$

Plugging in the values we get:

$-20 = (-50_$$sin$θ) $} t +\frac{1}{2} (-32.2} )t^{2}$

-20 = -32tanθ - 10.304$sec^{2}$θ

Upon solving the above quadratic equation, we get,

tanθ = 0.27 , -3.38

Therefore,

tanθ$_{1}$ = 0.27

θ$_{1}$ = 15.10°

and, tanθ$_{2}$ = -3.38

θ$_{2}$ = 73.51

Learn more about quadratic equation here:

brainly.com/question/17177510

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