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Delicious77 [7]
3 years ago
11

Um aluno pretende construir um aquecedor usando um enrolamento de fio. Experimenta e verifica que não

Physics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

dddjebdhdjwopdjhgvvdr

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Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton
solmaris [256]

Answer:

a

\lambda = 3.68 *10^{-36} \  m

b

\lambda_p = 1.28*10^{-14} \ m

Explanation:

From the question we are told that

   The mass of the person is  m =  180 \  kg

    The speed of the person is  v  =  1 \  m/s

    The energy of the proton is  E_ p =  5 MeV = 5 *10^{6} eV  = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \  J

Generally the de Broglie wavelength is mathematically represented as

      \lambda = \frac{h}{m * v }

Here  h is the Planck constant with the value

      h = 6.62607015 * 10^{-34} J \cdot s

So  

     \lambda = \frac{6.62607015 * 10^{-34}}{ 180  * 1  }

=> \lambda = 3.68 *10^{-36} \  m

Generally the energy of the proton is mathematically represented as

         E_p =  \frac{1}{2}  *   m_p  *  v^2_p

Here m_p  is the mass of proton with value  m_p  =  1.67 *10^{-27} \  kg

=>     8.0*10^{-13} =  \frac{1}{2}  *   1.67 *10^{-27}  *  v^2

=>   v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }

=>   v = 3.09529 *10^{7} \  m/s

So

        \lambda_p = \frac{h}{m_p * v_p }

so    \lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }

=>     \lambda_p = 1.28*10^{-14} \ m

     

5 0
3 years ago
solve the following system by any method 2x - 6y = 24 ... -5x + 6y = -6 ... A. (0,-6) B. (4,-1) C. (-6,-6) D. (6,-1)
vodka [1.7K]
Using elimination, the answer is C. 
5 0
3 years ago
Tenses of<br>write=<br>read=<br><br>​
PilotLPTM [1.2K]

Answer:

present

Explanation:

read doesn't change but write is in present tense

7 0
3 years ago
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfo
dolphi86 [110]

Answer:

Explanation:

To convert gram / centimeter³ to kg / m³

gram / centimeter³

= 10⁻³ kg / centimeter³

= 10⁻³  / (10⁻²)³ kg / m³

= 10⁻³ / 10⁻⁶ kg / m³

= 10⁻³⁺⁶ kg / m³

= 10³ kg / m³

So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³

2.33 gram / cm³

= 2.33 x 10³ kg / m³ .

3 0
3 years ago
A car travels 40km/hr for 2 hours and 55km/hr for 2 hours how far has the car traveled what’s its average velocity?
vfiekz [6]

Answer;

Average speed  = 47.5 km/hr

Explanation and solution;

Average Speed = Total distance /Total time

Total distance;

-In the first two hours travelling at 40km/hr, total distance traveled is 80km.

(40 × 2) = 80 km

-In next two hours distance covered is 110 km. (55 ×2)

Total distance = 110 + 80 = 190 km

Total time = 2 + 2 = 4 hours

Average Speed = Total distance /Total time

                          = 190/4

                         = 47.5 km/hr

7 0
3 years ago
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