Answer:
Explanation:
Given data:
mass of block is 
radius of block = 0.061 m
moment of inertia is 
D is distance covered by block = 0.65 m
speed of block is 1.705 m/s
From conservation of momentum we have
![0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times 0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l](https://tex.z-dn.net/?f=0.84%20%5Ctimes%209.81%20%5Ctimes%200.65%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%200.84%20%5Ctimes%201.705%5E2%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%206.2%20%5Ctimes%2010%5E%7B-3%7D%20%5B%5Cfrac%7B1.705%7D%7B0.061%7D%5D%5E2%20%2B%20E_l)
solving for energy loss
No, it will not fall. The pencil will remain at zero speed relative to the spacecraft and will orbit the earth with the spacecraft.
Answer:
5 N
Explanation:
Given that,
A large bar magnet of mass 0.4 kg exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away.
We need to find the force exerted by the small bar magnet on the large one.
We know that, every action has an equal and opposite reaction. Both action and reaction occur in pairs. The force acting on one object to another is same and in opposite direction on the other object.
Hence, the force exerted by the small bar magnet on the large one is also 5 N.
A coil of wire with a current flowing thru it becomes a magnet
