Question

Simplify sin theta/sqrt 1-sin^2 theta

Answer 1

$\text{Use:}\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\tan x=\dfrac{\sin x}{\cos x}$

$\dfrac{\sin\Theta}{\sqrt{1-\sin^2\Theta}}=\dfrac{\sin\Theta}{\sqrt{\cos^2\Theta}}=\dfrac{\sin\Theta}{\cos\Theta}=\tan\Theta$

Answer 2

$\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^{2}}}=\dfrac{\sin(\theta)}{\cos(\theta)}\\\\=\tan(\theta)$