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Marianna [84]
3 years ago
7

Least common factor of 15 and 20

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Answer: Lcm=60

Step-by-step explanation: but if you want lcf its always 1

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Solve the inequality: −2x > −6
Drupady [299]

Answer:

x < 3

Step-by-step explanation:

8 0
3 years ago
Use Theorem 2.1.1 to verify the logical equivalence. Give a reason for each step. -(pv –q) v(-p^q) = ~p
sertanlavr [38]

Answer:

The statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p, \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

Step-by-step explanation:

We need to prove that the following statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p with the use of Theorem 2.1.1.

So

\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv

\equiv (\lnot p \land \lnot(\lnot q))\lor(\lnot p \land \lnot q) by De Morgan's law.

\equiv (\lnot p \land q)\lor(\lnot p \land \lnot q) by the Double negative law

\equiv \lnot p \land (q \lor \lnot q) by the Distributive law

\equiv \lnot p \land t by the Negation law

\equiv \lnot p by Universal bound law

Therefore \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

4 0
3 years ago
Jessie has 160 rubber bracelets. She arranges the bracelets in piles of 40. Which model shows 160 ÷ 40?
Sergio [31]

Answer:

I am not sure what model you are talking about, no options to choose from

Step-by-step explanation:

You can divide both by 10, making the problem 16 / 4, which would look like 4 piles of four.

This means that the model that looks like 4 groups of 40

5 0
3 years ago
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kykrilka [37]
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3 years ago
Please help! Brainiest
insens350 [35]

Answer:

x=1

Step-by-step explanation:

x=1 then y=4

7 0
3 years ago
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