Answer:
t ≈ 235.47 secs
Explanation:
<u>Calculate how long it will take the transformation to go to 88% completion</u>
Given that Avrami equation ( <em>y </em>)= 1 - exp( - kt^n )
n = 2.3
t = 145 secs
reaction = 50% after t = 145 secs
Reaction = 88% after t = ?
attached below is a detailed solution
Answer:
An apple,a person.a table,a computer,wood because they occupies space
non matter=Light, heat, kinetic and potential energy, and sound are non-matter because they are massless
Sodium ion- it has 1 valence electron so its easy for it to loose this electron. Thus, it forms sodium ion by loosing its valence elctron while reacting.It forms Na+. ... Oxide ion- it has 6 valence electrons so it gains 2 electrons lost by a metal atom and reacts with it.
The mass of the formed precipitate of AgCl in the reaction is 1.29 grams.
<h3>How do we find moles from molarity?</h3>
Moles (n) of any substance from molarity (M) will be calculated by using the below equation:
M = n/V, where
V = volume in L
Given chemical reaction is:
2AgNO₃(aq) + CaCl₂(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)
- Moles of CaCl₂ = 0.150M × 0.03L = 0.0045 moles
- Moles of AgNO₃ = 0.100M × 0.015L = 0.0015 moles
From the stoichiometry of the reaction, mole ratio of AgNO₃ to CaCl₂ is 2:1.
0.0015 moles of AgNO₃ = reacts with 1/2×0.0045 = 0.00075 moles of CaCl₂
Here CaCl₂ is the limiting reagent, and formation of precipitate depends on this only.
Again from the stoichiometry of the reaction:
0.0045 moles of CaCl₂ = produces 2(0.0045) = 0.009 moles of AgCl
Mass of 0.009 moles AgCl will be calculated as:
n = W/M, where
- W = required mass
- M = molar mass = 143.45 g/mol
W = (0.009)(143.45) = 1.29g
Hence required mass of precipitate is 1.29 grams.
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Answer:
Long jump doesn't use the SI unit of measurement
