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kifflom [539]
3 years ago
8

A hybrid car averages 600 miles on a 12.9 gallon tank of gas. Manuel is planning a 1240-mile vacation in his hybrid car. Find ho

w many gallons of gas he can expect to burn.
Mathematics
2 answers:
natita [175]3 years ago
6 0
<span>the average distance travelled by the car - 600 miles
 amount of gas used up - 12.9 gallons
therefore when he travels 600 miles he uses up 12.9 gallons
                                                                                 
for every mile the amount of gas used up - 12.9 gallons / 600 miles = 0.0215 gallons / mile 
therefore 0.0215 gallons used up per mile
                                         
so when he's going for 1240 miles - gas used up is 0.0215 gallons/ mile x 1240 miles = 26.66 gallons
                                       
amount of gas needed is 26.66 gallons </span>
N76 [4]3 years ago
6 0

Answer:

26.66 gallon of gas

Step-by-step explanation:

A car uses 12.9 gallons of gas for travelling 600 miles

For travelling one mile , the car will use gas = 12.9 gallon of gas/600 miles  

= 0.0215 gallon of gas /mile

For travelling 1240 miles, gallon of gas required =  

= 0.0215 gallon of gas /mile x 1240 miles  

= 26.66 gallon of gas  

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You need 250 mL of a 90% alcohol solution. On hand, you have a 75% alcohol mixture. How much of the 75% alcohol mixture and pure
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Answer:

  • 100 mL of 75% solution
  • 150 mL of pure alcohol

Step-by-step explanation:

Let x represent the quantity (in mL) of pure alcohol needed for the mix. Then the amount of 75% needed is (250-x). The amount of alcohol in the mixture is ...

  1.00x +0.75(250 -x) = 0.90(250)

  0.25x +187.5 = 225 . . simplify

  0.25x = 37.5 . . . . . . . . subtract 187.5

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3 years ago
Write an equation in slope-intercept<br> form through (-8,9) through (-6,-6).
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Read 2 more answers
Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1
Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

        P.Q. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 101

              \sigma = population standard deviation

              n = sample size = 25

So, 90% confidence interval for the population mean test score, \mu is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.6449) = 0.90

P(-1.6449 * \frac{\sigma}{\sqrt{n} } < {Xbar-\mu} < 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

P(X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } < \mu < X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

90% confidence interval for \mu = [ X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } , X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ]

                                                  = [ 101 - 1.6449 * \frac{17}{\sqrt{25} } , 10 + 1.6449 * \frac{17}{\sqrt{25} } ]

                                                  = [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0
4 years ago
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