Answer:
V(average)=6.37 V
Explanation:
Given Data
Peak Voltage=10V
Frequency=10 kHZ
To Find
Average Voltage
Solution
For this first we need to find Voltage peak to peak
So
Voltage (peak to peak)= 2× voltage peak
Voltage (peak to peak)= 2×10
Voltage (peak to peak)= 20 V
Now from Voltage (peak to peak) formula we can find the Average Voltage
So
Voltage (peak to peak)=π×V(average)
V(average)=Voltage (peak to peak)/π
V(average)=20/3.14
V(average)=6.37 V
Answer:
1.9 s
Explanation:
We are given that
Length of cable=l=15 m
We have to find the time you have to move out of the way.
We know that
Time period,T=
Where g=
By using the formula


Time you have to move out

Hence,time you have to move out of the way=7.77 s
Answer:
<u>198785.714286 Joules</u>
Explanation:


<u>To find work:</u>
Now that the force and the distance are known, plug and chug:

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.
So, your answer is
<u>198785.714286 Joules</u>
Answer:
we will have induced magnetic field towards us
now in order to induce the magnetic field towards us we must have induced current in the loop and its direction is counterclockwise.
Explanation:
As per lenz law we know that the rate of change in magnetic flux linked with the closed loop will induced EMF in the loop and the direction of this induced current in the loop will always oppose the causes due to which it is induced
Here we know that magnetic field is straight towards us and it start decreasing with time
So we can say that flux linked with the coil will also decrease with time
Now as per lenz law the induced magnetic field of the loop is in such a direction that it will increase the magnetic flux in the coil.
So we will have induced magnetic field towards us
now in order to induce the magnetic field towards us we must have induced current in the loop and its direction is counterclockwise.