Question

3) connect two lamps to a power supply in series and current drawn from the power supply is is. connect the same two lamps in parallel and the current drawn from the power supply is ip. how does the current drawn by the series circuit compare to the current drawn by the parallel circuit?

Answer 1

The current drawn by the series circuit is(R₁ + R₂)/R₁R₂  times the current drawn by the parallel circuit.

Let the resistance of the two lamps are R₁ and R₂.

Then the equivalent resistance in series combination is: R = R₁ + R₂.

And,  the equivalent resistance in parallel combination is:

r = R₁R₂/(R₁ + R₂).

So, if the supply voltage is V,

Then, current drown in series combination; $i_s$ = V/R = V/(R₁ + R₂)

And, current drown in parallel combination; $i_p$ = V/r = V(R₁ + R₂)/R₁R₂

So ,$\frac{i_s}{i_p}$ = [ V/(R₁ + R₂)] /[V(R₁ + R₂)/R₁R₂]

=  (R₁ + R₂)/R₁R₂

Hence, the  ratio of current drawn in series and current drown in parallel is  (R₁ + R₂)/R₁R₂.  So, he current drawn by the series circuit is(R₁ + R₂)/R₁R₂  times the current drawn by the parallel circuit.

Learn more about electric current here:

brainly.com/question/2264542

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