Answer:
A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Explanation:
The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.
Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)
Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L
Number of moles of solute = ?
Volume of solution in L = 1 L
0.105 = Number of moles of solute × 1
Number of moles of solute = 0.105 mole
Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
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