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madam [21]
3 years ago
6

A solution labeled "0.105 M NaOH" would contain ______________ moles of NaOH in each liter of solution.

Chemistry
1 answer:
dem82 [27]3 years ago
7 0

Answer:

A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Explanation:

The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.

Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)

Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L

Number of moles of solute = ?

Volume of solution in L = 1 L

0.105 = Number of moles of solute × 1

Number of moles of solute = 0.105 mole

Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Hope this Helps!!!

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Explanation:

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Well I'm sure many a time you've seen on some science experiment someone wrap a copper wire around a nail well thats generally the idea for electromagnets you get a solid piece of iron which is the only metal that is magnetic and you wrap a copper wire around it and the idea is to make two opposing magnetic poles by aligning the molecules with a electrical charge (a battery) so now with all three pieces assembles you have a copper wire attached to two sides of a battery and wrapped around a nail
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3 years ago
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8. What volume (ml) of a 5.45 M lead nitrate solution must be diluted to 820.7 ml to make a
Ganezh [65]

212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

Answer:

Option A.

Explanation:

Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.

C_{1} V_{1} =C_{2} V_{2}

So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.

Then, (5.45*V_{1} ) = (820.7*1.41)

V_{1}=\frac{820.7*1.41}{5.45}=  212.33 ml

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3 0
2 years ago
Calculate the p value of each ion indicated:
Nataliya [291]
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12 x 10^-2 approx  = normality

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now, after getting the pKa put it in formula  :
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hope this helps
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2 years ago
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Vaselesa [24]

Answer:

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Explanation:

When sodium contact with water it loses its one electron and thus gain positive charge. When there are more sodium atoms present and many atoms do this thus more positive ions are produced and these positive ions repeal each other at high speed and explosion occur.

But when it form compound with other material, it will not showed this behavior.

Example:

Consider the sodium chloride, when it dissolve in water sodium not showed explosion. In sodium chloride sodium already gives its electron to the chlorine and have stable electronic configuration. The sodium present in cationic form. When it dissolve, partial positive charge of water surrounds the Cl⁻ and partial negative charge of water surrounds the Na⁺ ion, ans sodium chloride gets dissolve into water without explosion.

6 0
3 years ago
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