All categories

3 years ago

What is the percentage of hydrogen in c2h4

Chemistry

1 answer:

jarptica [38.1K]3 years ago

8 0

Ethylene- C2H4 = 85.7% Carbon and 14.3% Hydrogen

Find the atomic masses for each element and multiply it by the number of atoms in the compound, then add.

C- 12.0 * 2= 24.0

H- 1.00 * 4= 4.00

-----------------------

28.0

Take the masses for each element and divide it by the total mass. Then change the answer to get the percent.

C 24.0 / 28.0= .857 = 85.7%

H 4.00 / 28.0= .143 = 14.3%

<h3>Ethylene is 85.7% Carbon and 14.3% Hydrogen </h3>

You might be interested in

The specific silver is How many joules of energy are needed to warm 4.37 g of silver from 25.0 degrees * C to 27.5 degrees * C ?

Alexxandr [17]

0.24J/g*degC * 4.37g * 2.5degC = 2.622J

The 2.5 degC is the difference between 25 and 27.5 deg C.

6 0

4 years ago

PLEASE HELP CHEMISTRY

eduard

When sodium carbonate is dissolved in water, the equation is $Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$ .

When carbon dioxide is placed in water, aqueous carbon dioxide is formed: $CO_2 (g) --- > CO_2(aq)$

<h3>Dissolution of compounds in water</h3>

Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.

Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.

While in solution, sodium carbonate dissociates into its component ions according to the following equation:

$Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$

Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.

Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as: $CO_2 (g) --- > CO_2(aq)$

More on the dissolution of substances can be found here: brainly.com/question/28580758

#SPJ1

7 0

1 year ago

Science, please help and thank you!!

lapo4ka [179]

Swings hope this helps

8 0

3 years ago

How many moles are in 1.05 g of gold (Au)?

Wittaler [7]

Answer:

0.005 mol

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = given mass of Gold = 1.05 g ,

m = molecular mass of Gold = 197 g/mol

<u>Hence , moles can be calculated as -</u>

n = w / m = 1.05 g / 197 g/mol = 0.005 mol

7 0

3 years ago

Give the number of significant figures indicated 6.695

Genrish500 [490]

3 significant figures

5 0

3 years ago

Read 2 more answers