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Zinaida [17]
2 years ago
8

Even when an object appears to be at rest, its atoms and molecules are in constant motion

Chemistry
1 answer:
natita [175]2 years ago
5 0

Answer:

the answer is True

Explanation:

the answer is True

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A 6.0 Liter solution is made with 2 moles of solute. What is the molarity of the solution?
kodGreya [7K]
The formula for molarity is: mol/L. so it would be 2.0 mol/ 6.0 L.

the answer is: .33 M

hope this helps!
3 0
3 years ago
What thype of bond requires the give and take of electrons ?
DedPeter [7]
Ionic bond involves electrostatic attraction between oppositely charged ions.
The ions are atoms that have gained 1 or more electrons and atoms that have lost 1 or more electrons.
<span>Answer: The type of bond that requires the give and take of electrons is Ionic bond</span>
6 0
3 years ago
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Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The n
NISA [10]

Answer:

8.37 grams

Explanation:

The balanced chemical equation is:

C₆H₁₂O₆     ⇒   2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass  of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT    ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂  x  ( 1 mol C₆H₁₂O₆   / 2 mol CO₂ ) =  0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g

5 0
3 years ago
ANSWER ASAP IF YOU KNOW THIS ......What is the mass number of this atom?
trasher [3.6K]
The correct answer is 7 I just took the test :)
6 0
3 years ago
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Compared to oil and gas, solar energy:
prohojiy [21]
Cost more. Gas and oil have a very steady low price, and also the sun is not always out.
Does that help?
6 0
3 years ago
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