Answer: A fuse
Explanation:
A fuse is a thin piece of wire that heats and melts when the electric current in a circuit exceeds a safe value, thereby tripping the circuit and cutting off the electric current flow.
Answer:
a) ![v_2=35.60ft/sec](https://tex.z-dn.net/?f=v_2%3D35.60ft%2Fsec)
b) ![h_2=45ft](https://tex.z-dn.net/?f=h_2%3D45ft)
Explanation:
From the question we are told that:
Weight ![W=100lbf](https://tex.z-dn.net/?f=W%3D100lbf)
Decrease in kinetic energy ![dK.E= 500 ft lbf](https://tex.z-dn.net/?f=dK.E%3D%20500%20ft%20lbf)
Increase in potential energy ![dP.E =1500 ft lbf.](https://tex.z-dn.net/?f=dP.E%20%3D1500%20ft%20lbf.)
Velocity ![V_1=40](https://tex.z-dn.net/?f=V_1%3D40)
Elevation ![h=30ft](https://tex.z-dn.net/?f=h%3D30ft)
![g=32.2 ft/s2](https://tex.z-dn.net/?f=g%3D32.2%20ft%2Fs2)
a)
Generally the equation for Change in Kinetic Energy is mathematically given by
![dK.E=\frac{1}{2}m(v_1^2-v_2^2)](https://tex.z-dn.net/?f=dK.E%3D%5Cfrac%7B1%7D%7B2%7Dm%28v_1%5E2-v_2%5E2%29)
![500=\frac{1}{2}*\frac{100}{32.2}(v_1^2-v_2^2)](https://tex.z-dn.net/?f=500%3D%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B100%7D%7B32.2%7D%28v_1%5E2-v_2%5E2%29)
![v_2=35.60ft/sec](https://tex.z-dn.net/?f=v_2%3D35.60ft%2Fsec)
b)
Generally the equation for Change in Potential Energy is mathematically given by
![dP.E=mg(h_2-h_1)](https://tex.z-dn.net/?f=dP.E%3Dmg%28h_2-h_1%29)
![1500=mg(h_2-h_1)](https://tex.z-dn.net/?f=1500%3Dmg%28h_2-h_1%29)
![h_2=45ft](https://tex.z-dn.net/?f=h_2%3D45ft)
The correct
answer between all the choices given is the second choice or letter B. I am
hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.
The solution would
be like this for this specific problem:
<span>M=<span>P/V</span></span>
<span>M=<span>8/10</span></span>
<span><span>M=0.8</span></span>
Answer:
c
Explanation:
protons are the postive charge in your nucleus in the cell
Answer
Work done will be
and it will be positive
Explanation:
We have given charge ![2.1\times 10^{-6}C](https://tex.z-dn.net/?f=2.1%5Ctimes%2010%5E%7B-6%7DC)
We have to find work done in moving the charge from 15 volt to 8 volt
Let ![V_1=15V\ and\ V_2=8volt](https://tex.z-dn.net/?f=V_1%3D15V%5C%20and%5C%20V_2%3D8volt)
So potential difference ![V=V_1-V_2=15-8=7volt](https://tex.z-dn.net/?f=V%3DV_1-V_2%3D15-8%3D7volt)
We know that work done
, here Q is charge and V is potential difference
So work done ![W=QV=2.1\times 10^{-6}\times 7=14.7\times 10^{-6}J](https://tex.z-dn.net/?f=W%3DQV%3D2.1%5Ctimes%2010%5E%7B-6%7D%5Ctimes%207%3D14.7%5Ctimes%2010%5E%7B-6%7DJ)
It will be positive work done because work is done in moving charge from higher potential to lower potential