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kari74 [83]
3 years ago
11

You are driving to the grocery store at 20 m/s. You are 110 m from an intersection when the light turns red. You have a reaction

time of 0.70 seconds before applying the brakes.
a) How far from the intersection are you when you hit the brakes?
b) What deceleration is required to stop at the intersection?
c) How long does it take you to stop?
Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

a)

reaction time = 0.70 s

distance travelled in reaction time = v*t

= 20 m/s * 0.70 s

= 14 m

So, when brake is applied, distance remaining= 110 m - 14 m = 96 m

Answer: 96 m

b)

vf = 0 m/s

d = 96 m

vi = 20 m/s

use:

vf^2 = vi^2 + 2*a*d

0 = 20^2 + 2*a*96

-400 = 2*a*96

a = -2.08 m/s^2

Answer: -2.08 m/s^2

c)

use:

vf = vi + a*t

0 = 20 - 2.08*t

t = 9.6 s

Answer: 9.6 s

Explanation:

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Read 2 more answers
A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is release
DiKsa [7]

Answer:

The charge on the bead is  q = 6.084 *10^{-7}\ C

Explanation:

From the question we are told that

     The  mass of the bead is  m  =  3.6 \ g =  0.0036 \ kg

      The  magnitude of the electric field is  E =  200,000 \ N/C

       The  acceleration of the bead is  a =  24 m/s^2

Generally,  the  electric force on the bead is  mathematically represented as  

         F_ e =  q E

Where q is the charge on the bead

   Now the gravitational force opposing the upward movement of the bead is  mathematically represented as

       F_g  =  mg

Generally the net force on the bead is  mathematically represented as

       F  =  F_e - F_g = m* a

=>    qE -  mg  = ma

Now substituting values

       q *  200000 -   0.0036 *9.8   = 0.0036 * 24

     q = 6.084 *10^{-7}\ C

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