<h2>
Depth of river is 4.48 m</h2>
Explanation:
Discharge = Area x Velocity
Discharge of river = Discharge of stream 1 + Discharge of stream 2

Area of stream 1 = w₁ x d₁ = 8.9 x 3.8 = 33.82 m²
Area of stream 2 = w₂ x d₂ = 6.5 x 3.9 = 25.35 m²
Velocity of stream 1 = 2.3 m/s
Velocity of stream 2 = 2.6 m/s
Velocity of river = 3 m/s

Substituting

Depth of river = 4.48 m
Answer:
5.37 m/s
0.98 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²

Velocity of the ball when it passes an observer sitting at a window is 5.37 m/s

Time taken by the ball to pass the observer sitting at a window is 0.98 seconds
The correct option is (D) Both, distance traveled and displacement are 300 km.
Why?
To solve the problem we must remember what distance and displacement means.
Distance means the ground/space covered in a certain time, in physics, distance is equal to the product of the speed and time.
Displacement means the distance between the starting and ending point of an object after (or not) being in motion.
So, for the problem, using the graphic we are asked to find the distance and displacement in 4 hours
We can see that in 4 hours, the distance covered is 300km, also, we can see that the difference (in distance) between the starting point at 0 hours and the ending point at 4 hours is equal to the distance covered in the same time.
Hence, we can see that the correct option is D) Both, distance traveled and displacement are 300 km.
Have a nice day!
The smaller surface area
Hope this helps!