<u>To find the mass, with only the weight</u>:
⇒ must consider the relationship between the mass and weight
⇒ (<em>in other words</em>) we must find the equation that has both the
mass and weight
<u>Based on our physics knowledge, we know</u>:
- Weight: 147N
- Gravitational Acceleration: 9.8 m/s²
<u>Now let's plug in the values, and solve</u>:
<u>Answer: 15 kg</u>
Hope that helps!
<em>*as a note, if you use the gravitational acceleration as 10m/s², then the answer would be 14.7 kg</em>
Answer:920.31 J
Explanation:
Given
Volume of water (V)
mass(m)
Temperature 
Final Temperature 
specific heat of water(c)
Therefore heat required to removed is
The answer is the diameter of the cam shaft.
This is used to compute for the area of the circle so you can multiply it with the rocker ratio to get maximum amount of weight the valve can lift.
Up until the moment the box starts to slip, the static friction is maximized with magnitude <em>f</em>, so that by Newton's second law,
• the net force acting on the box parallel to the ramp is
∑ <em>F</em> = <em>mg</em> sin(<em>α</em>) - <em>f</em> = 0
where <em>mg</em> sin(<em>α</em>) is the magnitude of the parallel component of the box's weight; and
• the net force acting perpendicular to the ramp is
∑ <em>F</em> = <em>n</em> - <em>mg</em> cos(<em>α</em>) = 0
where <em>n</em> is the magnitude of the normal force and <em>mg</em> cos(<em>α</em>) is the magnitude of the perpendicular component of weight.
From the second equation we have
<em>n</em> = <em>mg</em> cos(<em>α</em>)
and <em>f</em> = <em>µn</em> = <em>µmg</em> cos(<em>α</em>), where <em>µ</em> is the coefficient of static friction. Substituting these into the first equation gives us
<em>mg</em> sin(<em>α</em>) = <em>µmg</em> cos(<em>α</em>) ==> <em>µ</em> = tan(<em>α</em>) ==> <em>α</em> = arctan(0.35) ≈ 19.3°
