Answer:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
Explanation:
In given chemical equation the aqueous lead (II) nitrate react with aqueous potassium chloride and form aqueous potassium nitrate and lead chloride.
Chemical equation:
Pb (NO₃)₂(aq) + KCl(aq) → KNO₃(aq) + PbCl₂(s)
Balanced chemical equation:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
ionic equation:
Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺(aq) + 2Cl⁻ (aq) → 2NO₃⁻(aq) + 2K⁺(aq) + PbCl₂(s)
Net ionic equation:
Pb²⁺ (aq) + 2Cl⁻ (aq) → PbCl₂(s)
The NO₃⁻(aq) and K⁺(aq) are spectator ions that's why these are not written in net ionic equation. The PbCl₂ can not be splitted into ions because it is present in solid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
