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2 years ago

Aqueous magnesium chloride is not used to extract magnesium. Explain why.

1 answer:

4 0

Explanation: Magnesium chloride, MgCl2, dissolved in seawater, is an abundant, natural source of the very useful metal magnesium. Magnesium is a common component of alloys. Alloys are produced by combining a pure metal with one or more other elements to form a new substance with desirable properties. (Steel, for example, is a common alloy of iron and carbon.) Magnesium alloys are found in aircraft, automobiles, rockets, luggage frames, portable power tools, cameras, laptop computer casings and mobile phones.

Magnesium lends lightness and strength to alloys—a real plus for the owners of fuel-consuming vehicles, or travelers carting luggage. And magnesium alloy construction helps dampen the noise and vibration associated with the use of hand-held power tools, such as electric drills and nail-shooting guns.

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At a certain temperature, iron (II) oxide, FeO, can react with carbon monoxide, CO, to form elemental iron, Fe, and carbon dioxi

barxatty [35]

Answer:

The pressure of CO2 at the equilibriumis 0.185 atm

Explanation:

Step 1: Data given

The value of Kp at that temperature is 0.242

FeO was initially in a container with CO at a pressure of 0.95 atm

Step 2: The balanceequation

FeO(s) + CO(g) ⟷ Fe(s) + CO2(g)

Step 3:The initial pressure

pCO = 0.95 atm

pCO2 = 0 atm

Step 4: The pressure at the equilibrium

pCO = 0.95 - x atm

pCO2 = X atm

Step 5: Calculate Kp

Kp = pCO2 / pCO

0.242 = X / (0.95 - X)

X = 0.185

pCO = 0.95 - 0.185 = 0.765 atm

pCO2 = 0.185 atm

The pressure of CO2 at the equilibriumis 0.185 atm

7 0

3 years ago

4) What is the IUPAC name of this compound?

zheka24 [161]

Answer:

1,3- dichlorobutane

Explanation:

The IUPAC name of given compound is 1,3- dichlorobutane.

First of all we will select the longest chain.

The given compound is straight chain. So the compound have four carbon atoms means parent name will butane.

Then we will see the position of functional group. Gives the lowest possible number to the functional group attached.

In given compound one chlorine atom is attached on left side and other is on right side. we will start the numbering from left because in this way chlorine will get lowest possible number which 1 and 3.

As we start the numbering from left the one chlorine atom get number one and other is attached on carbon 3 will have number 3.

There are two chlorine atoms so we will give name "dichloro"

The name will be,

⁴CH₃-³CHCl-²CH₂-¹CH₂Cl

1,3- dichlorobutane.

8 0

4 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Ratling [72]

Jot down the formula of the ionic compound. Let's say the ionic compound you're working with is NaCl.

Write the name of the metal.

Add the name of the non-metal with an –ide ending.

Combine the cation and anion names.

Practice naming more simple ionic compounds.

7 0

3 years ago

Why is zinc not extracted from ZnO through reduction using CO?

Jet001 [13]

The standard Gibbs free energy of formation of ZnO from Zn is lower than that of CO2 from CO. Therefore, CO cannot reduce ZnO to Zn. Hence, Zn is not extracted from ZnO through reduction using CO

6 0

1 year ago

Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O

Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

I hope it helps!

5 0

3 years ago