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nika2105 [10]
2 years ago
5

Which process is a physical change?

Chemistry
2 answers:
kipiarov [429]2 years ago
6 0

Water boiling is a physical change. Physical changes do not change the substance's makeup; boiling, melting, and other changes in matter are physical because they do not alter the substance, while the other choices do change the chemical makeup of the substance.

Semenov [28]2 years ago
3 0
C is the correct answer
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21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
Which is the largest thing in the world???????????
Ksivusya [100]

<em>S</em><u><em>equoia trees</em></u> are the largest thing in the world or planet

thanx

<u>h</u><u><em>ope it helps you mark as brainlest</em></u>

5 0
3 years ago
Read 2 more answers
Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI
NeTakaya

Answer :

AgI should precipitate first.

The concentration of Ag^+ when CuI just begins to precipitate is, 6.64\times 10^{-7}M

Percent of Ag^+ remains is, 0.0076 %

Explanation :

K_{sp} for CuI is 1\times 10^{-12}

K_{sp} for AgI is 8.3\times 10^{-17}

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

CuI\rightleftharpoons Cu^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Cu^+][I^-]

1\times 10^{-12}=0.0079\times [I^-]

[I^-]=1.25\times 10^{-10}M

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

AgI\rightleftharpoons Ag^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^+][I^-]

8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M

[Ag^+]=6.64\times 10^{-7}M

Now we have to calculate the percent of Ag^+ remains in solution at this point.

Percent of Ag^+ remains = \frac{6.64\times 10^{-7}}{0.0087}\times 100

Percent of Ag^+ remains = 0.0076 %

8 0
3 years ago
A small, hard-shelled fossil that resembles a modern-day ocean organism was found
Paul [167]

Answer:

The desert was one covered by ocean water.

Explanation:

5 0
2 years ago
Cómo se forma el enlace ionico​
scoundrel [369]

Answer:

El enlace iónico se forma por transferencia de electrones entre metales y no metales. El enlace covalente se forma al compartir electrones entre no metales.

Explanation:

5 0
2 years ago
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