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Zepler [3.9K]
3 years ago
14

Diesel fuel is used in the engine of trucks that carry dirt fruit and other cargo. Fuel is burned in engines to make the motor m

ove. Which of these is the main energy transformation as the truck engines use the fuel?
Physics
1 answer:
Marina86 [1]3 years ago
4 0

Answer: Fuel is burned in engines to make the motor move.

( Chemical to Mechanical )

Explanation:

during combustion of the diesel ( when the fuel is burnt in the engine of the vehicle, the diesel ( chemical energy ) is transformed or converted to Mechanical energy. This mechanical energy is what the truck uses in moving. Without the combustion of the fuel the vehicle won’t move and the combustion of diesel is achieved through compression unlike that of fuel.

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La estrella mas proxima a la tierra esta a 2 años de luz. Calcula esta distancia en unidades del SI
tino4ka555 [31]

Answer:

2\ ly=1.89\times 10^{16}\ m

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

1\ ly=9.461\times 10^{15}\ m

2 light-years means,

2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m

So, the required distance is equal to 1.89\times 10^{16}\ m.

5 0
3 years ago
In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst
dem82 [27]

Answer:

r_\alpha=16cm

Explanation:

The radius of the circumference described by a particle in a cyclotron is given by:

r=\frac{mv}{qB}(1)

m is the particle's mass, v is the speed of the particle, q is the particle's charge and B is the magnitude of the magnetic field.

Kinetic energy is defined as:

K=\frac{mv^2}{2}=\frac{m^2v^2}{2m}\\

Solving this for mv:

mv=\sqrt{2mK}(2)

Replacing (2) in (1):

r=\frac{\sqrt{2mK}}{qB}

For protons, we have:

r_p=\frac{\sqrt{2m_pK}}{eB}(3)

For alpha particles, we have:

r_\alpha=\frac{\sqrt{2m_\alpha K}}{(2e)B}(4)

Dividing (4) in (3):

\frac{r_\alpha}{r_p}=\frac{\frac{\sqrt{2m_\alpha K}}{(2e)B}}{\frac{\sqrt{2m_p K}}{(e)B}}\\r_\alpha=\frac{r_p}{2}\sqrt{\frac{m_\alpha}{m_p}}\\r_\alpha=\frac{16cm}{2}\sqrt{\frac{6.64*10^{-27}kg}{1.67*10^{-27}kg}}\\r_\alpha=\frac{16cm}{2}(\sqrt{3.98})\\\\r_\alpha=\frac{16cm}{2}(2)\\r_\alpha=16cm

4 0
4 years ago
Objects A and B are brought close to each other. Object A will soon become positively charged. Identify the charge that must tra
tamaranim1 [39]
The answer to this question would be: Object B must become negatively charged.
An object with a positive charge will exert pulling force to object with a negative charge but will push an object with a positive charge. If object A and B brought close together and object A have a positive charge, object B must be turned into a negative charge.
3 0
3 years ago
Read 2 more answers
A 50 kg student climbs 3 m to the top of a set of stairs.
VashaNatasha [74]
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mass 50 kg; height 3; g 9.81
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3.Power=work×time
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3 0
3 years ago
Newton’s third law in football?
trapecia [35]
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In short, when the football is throw, there is a reaction with the ball and the player accordingly with the force put into the ball.
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3 years ago
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