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vaieri [72.5K]
3 years ago
12

¿Cómo es el movimiento uniforme de los pedales de una bicicleta con respeto a la tierra y con respecto al ciclista?

Physics
1 answer:
Nastasia [14]3 years ago
6 0
Respecto al ciclista
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In a chemical reaction, the total charge of the reactants must be
MA_775_DIABLO [31]

the same with that of products

Explanation:

In a chemical reaction, the total charge of the reactants must be the same with that of products.

Charges must be conserved or balanced in chemical reactions.

  • In both acidic and basic/neutral medium electrons are used to balance the charge.
  • The appropriate number of electrons is added to the side with a larger charge.
  • One electron is used to balance each positive charge.
  • This ensures that the sum of charges on both sides the same.

Learn more:

Balanced equation brainly.com/question/5297242

#learnwithBrainly

4 0
3 years ago
A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o
Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

dE = k\dfrac{dQ}{r^2}cos(\theta ) <em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>

where r is the radius of curvature.

Now

dQ = \lambda rd\theta,

where \lambda is the charge per unit length, and it has the value

\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.

Thus, the electric field at the center of the curvature of the arc is:

E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

Now, we find \theta_1 and \theta_2. To do this we ask ourselves what fraction is the arc length  3.0 of the circumference of the circle:

fraction = \dfrac{3.0m}{2\pi (2.3m)}  = 0.2076

and this is  

0.2076*2\pi =1.304 radians.

Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

4 0
3 years ago
Emmit is lifting a box vertically which forces are necessary for calculating the total force
zavuch27 [327]

Answer:

FG and FP

Explanation:

Gravitational Force(FG) because the box is being pulled down and a resistance force pushing up because he is pushing(FP) up on the box.

I hope this helps!

4 0
2 years ago
A lamp has a power of 120 W and is left on for 24 hours . A television has a power of 350 W and is left on for three hours . com
Paladinen [302]
This is a power problem which requires the rearranging of a formula. The lamps energy used is 5 N, and the TV’s usage is 116.7 N (rounded from 116.6666repeating). Here my work:
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Does poop come out the pp or the butt please help im so confused best awnser gets brainleist
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Answer:

no poop comes out from your but

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