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vaieri [72.5K]
3 years ago
12

¿Cómo es el movimiento uniforme de los pedales de una bicicleta con respeto a la tierra y con respecto al ciclista?

Physics
1 answer:
Nastasia [14]3 years ago
6 0
Respecto al ciclista
You might be interested in
0.318 cm. What is the ideal mechanical advantage?
vodomira [7]

The ideal mechanical advantage will be 8.017. The ideal mechanical advantage value may be grater than the actual value of mechanical advantage.

<h3>What is mechanical advantage ?</h3>

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtained efficiency of  forces in levers and pulley.

The ideal mechanical advantage is found as;

\rm IMA = \frac{d \pi}{l} \\\\ \rm IMA = \frac{0.812 \times  \pi}{0.318} \\\\ IMA=8.017

The ideal mechanical advantage will be 8.017.

To learn more about the mechanical advantage, refer to the link;

brainly.com/question/7638820

#SPJ1

5 0
3 years ago
You have a box of filled with gas and by some process you double the number of atoms in the box, but now each one only has (on a
Fed [463]

Answer:

<u>Option-(D):</u>Thermal energy unchanged, temperature decreased.

Explanation:

<u>Thermal energy and Temperature,T:</u>

Thermal energy of the system is remained unchanged while the temperature,T of the objects present inside the system is more associated with the objects fundamental properties which each matter shows or exhibits in nature.

While the thermal energy is the flow or exchange of thermal or heat energy between the different objects in interaction to each other.

7 0
3 years ago
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the dist
Sidana [21]

Complete Question

The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.08m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 2.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2

Answer:

The acceleration due to gravity is  g = 167.2 \ m/s^2  

Explanation:

From the question we are told that

     The length of the simple pendulum is L = 1.081.08 \ m

      The number of cycles is  N =  101

       The time take is  t =  2.00 *10^{2 \ }s

Generally the period of this oscillation is mathematically evaluated as

         T = \frac{N}{t }

substituting values

         T = \frac{101}{2.0*10^2 }

        T = 0.505 \  s

The period of this oscillation is mathematically represented  as

               T = 2 \pi \sqrt{\frac{l}{g} }

making g the subject of the formula we have

              g = \frac{L}{[\frac{T}{2 \pi } ]^2 }

              g = \frac{4 \pi ^2 L }{T^2 }

Substituting values

               g = \frac{4 * 3.142 ^2  * 1.08 }{505.505^2 }

               g = \frac{4 * 3.142 ^2  * 1.08 }{0.505^2 }  

              g = 167.2 \ m/s^2  

7 0
3 years ago
A black hole is a ________
masya89 [10]

Answer:

Answer to the question:

Explanation:

A black hole is a finite region of space within which there is a mass concentration high and dense enough to generate a gravitational field such that no material particle, not even light, can escape it.

8 0
3 years ago
A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectiona
sweet [91]

Answer:

Y = 2.27 \times 10^{10} N/m^2

Explanation:

Natural length of the string is given as

L_o = 43 cm

length of the string while block is hanging on it

L = 53 cm

extension in length is given as

\Delta L = 10 cm

now we have strain in the string is given as

strain = \frac{\Delta L}{L}

strain = \frac{{10 cm}{43 cm}

strain = 0.23

similarly we will have cross-sectional area of the string is given as

A = 40 \times 10^{-6} m^2

now the stress in the string is given as

Stress = \frac{T}{A}

Stress = \frac{mg}{A}

Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}

stress = 9.07 \times 10^5 N/m^2

Now Young's Modulus is given as

Y = \frac{stress}{strain}

Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}

Y = 2.27 \times 10^{10} N/m^2

5 0
3 years ago
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